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\(10-(\mathrm{n}+4)=3\) What value of n is the solution to the given equation? -{3} 3 11 9...

GMAT Algebra : (Alg) Questions

Source: Prism
Algebra
Linear equations in 1 variable
EASY
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Notes
Post a Query

\(10-(\mathrm{n}+4)=3\)

What value of n is the solution to the given equation?

  1. \(-3\)
  2. \(3\)
  3. \(11\)
  4. \(9\)
A
\(\mathrm{-3}\)
B
\(\mathrm{3}\)
C
\(\mathrm{11}\)
D
\(\mathrm{9}\)
Solution

1. INFER the solution strategy

  • We have a linear equation with parentheses: \(\mathrm{10-(n+4)=3}\)
  • Strategy: First distribute the negative sign, then combine like terms, then isolate the variable

2. SIMPLIFY by distributing the negative sign

  • \(\mathrm{10-(n+4)}\) becomes \(\mathrm{10-n-4}\)
  • Remember: The negative sign applies to everything inside the parentheses
  • Our equation is now: \(\mathrm{10-n-4=3}\)

3. SIMPLIFY by combining like terms

  • On the left side: \(\mathrm{10-4=6}\)
  • Our equation becomes: \(\mathrm{6-n=3}\)

4. SIMPLIFY to isolate the variable term

  • Subtract 6 from both sides: \(\mathrm{6-n-6=3-6}\)
  • This gives us: \(\mathrm{-n=-3}\)

5. SIMPLIFY to solve for n

  • Since we have \(\mathrm{-n=-3}\), multiply both sides by -1
  • Final result: \(\mathrm{n=3}\)

Answer: B) 3




Why Students Usually Falter on This Problem


Most Common Error Path:

Weak SIMPLIFY execution: Sign error when distributing the negative sign

Students often write \(\mathrm{10-(n+4)}\) as \(\mathrm{10-n+4}\) instead of \(\mathrm{10-n-4}\). They forget that the negative sign must be distributed to both terms inside the parentheses.

Following this error path:

\(\mathrm{10-n+4=3}\)

\(\mathrm{14-n=3}\)

\(\mathrm{-n=-11}\)

\(\mathrm{n=11}\)

This may lead them to select Choice C (11)


Second Most Common Error:

Weak SIMPLIFY execution: Forgetting the final step to solve for n

Students correctly work through the problem until they reach \(\mathrm{-n=-3}\), but then stop or incorrectly think this means \(\mathrm{n=-3}\). They forget to multiply both sides by -1 to get the positive value of n.

This may lead them to select Choice A (-3)


The Bottom Line:

This problem tests careful execution of algebraic procedures, particularly managing negative signs. Success requires systematic application of distribution and solving techniques without rushing through the sign changes.

Answer Choices Explained
A
\(\mathrm{-3}\)
B
\(\mathrm{3}\)
C
\(\mathrm{11}\)
D
\(\mathrm{9}\)
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