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Question:A polynomial P is defined by P = 12y^2 + 30.Which expression is equivalent to P?

GMAT Advanced Math : (Adv_Math) Questions

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Advanced Math
Equivalent expressions
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Question:

A polynomial \(\mathrm{P}\) is defined by \(\mathrm{P = 12y^2 + 30}\).
Which expression is equivalent to \(\mathrm{P}\)?

A
\(6(2\mathrm{y}^2 + 5)\)
B
\(6(2\mathrm{y}^2 + 15)\)
C
\(6\mathrm{y}(2\mathrm{y} + 5)\)
D
\(12(\mathrm{y}^2 + 15)\)
Solution

1. INFER the problem type and strategy

  • This is asking for an equivalent expression to \(\mathrm{P = 12y^2 + 30}\)
  • Since we want an equivalent form and the answer choices show factored expressions, this is a factoring problem
  • Strategy: Find the greatest common factor (GCF) of all terms

2. SIMPLIFY to find the GCF

  • For the numerical coefficients:
    • \(\mathrm{12 = 2^2 \times 3}\)
    • \(\mathrm{30 = 2 \times 3 \times 5}\)
    • GCF of coefficients = \(\mathrm{2 \times 3 = 6}\)
  • For the variable parts:
    • First term: \(\mathrm{y^2}\)
    • Second term: no y
    • GCF of variables = 1 (no common variable factor)
  • Overall GCF = 6

3. SIMPLIFY by factoring out the GCF

  • Factor out 6 from each term:
    \(\mathrm{12y^2 + 30 = 6(2y^2) + 6(5) = 6(2y^2 + 5)}\)

4. Verify the answer

  • Distribute back: \(\mathrm{6(2y^2 + 5) = 12y^2 + 30}\)

Answer: A


Why Students Usually Falter on This Problem

Most Common Error Path:

Weak SIMPLIFY execution: Incorrectly including y as part of the GCF when the constant term has no y factor.

Students see \(\mathrm{y^2}\) in the first term and mistakenly think y should be factored out from both terms. They attempt: \(\mathrm{12y^2 + 30 = 6y(2y + ?)}\) but then get stuck because 30 doesn't contain y. Some force it anyway and write \(\mathrm{6y(2y + 5)}\), not realizing this gives \(\mathrm{12y^2 + 30y}\) instead of \(\mathrm{12y^2 + 30}\).

This may lead them to select Choice C (\(\mathrm{6y(2y + 5)}\)).

Second Most Common Error:

Poor SIMPLIFY execution: Making arithmetic errors when dividing the constant term by the GCF.

Students correctly identify 6 as the GCF but make a calculation error: \(\mathrm{30 \div 6 = 15}\) instead of \(\mathrm{30 \div 6 = 5}\). This gives them \(\mathrm{6(2y^2 + 15)}\).

This may lead them to select Choice B (\(\mathrm{6(2y^2 + 15)}\)).

The Bottom Line:

Success requires systematically finding the GCF by looking at what ALL terms have in common, not just focusing on one term. The constant term 30 has no variable factors, so y cannot be part of the GCF.

Answer Choices Explained
A
\(6(2\mathrm{y}^2 + 5)\)
B
\(6(2\mathrm{y}^2 + 15)\)
C
\(6\mathrm{y}(2\mathrm{y} + 5)\)
D
\(12(\mathrm{y}^2 + 15)\)
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