Which expression is equivalent to 15b^2 - 6b^2 + 3b^2? 6b^2 9b^2 12b^2 18b^2...
GMAT Advanced Math : (Adv_Math) Questions
Source: Prism
Advanced Math
Equivalent expressions
EASY
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Notes
Post a Query
Which expression is equivalent to \(15\mathrm{b}^2 - 6\mathrm{b}^2 + 3\mathrm{b}^2\)?
- \(6\mathrm{b}^2\)
- \(9\mathrm{b}^2\)
- \(12\mathrm{b}^2\)
- \(18\mathrm{b}^2\)
A
\(6\mathrm{b}^2\)
B
\(9\mathrm{b}^2\)
C
\(12\mathrm{b}^2\)
D
\(18\mathrm{b}^2\)
Solution
1. INFER what the problem is asking
- We need to find an equivalent expression for \(\mathrm{15b^2 - 6b^2 + 3b^2}\)
- "Equivalent" means the expressions have the same value for any value of b
2. INFER the approach
- All three terms have the same variable part: \(\mathrm{b^2}\)
- These are like terms, so we can combine them by working with their coefficients
- Keep the variable part \(\mathrm{(b^2)}\) and add/subtract the numbers in front
3. SIMPLIFY by combining the like terms
- \(\mathrm{15b^2 - 6b^2 + 3b^2 = (15 - 6 + 3)b^2}\)
- Calculate the coefficients: \(\mathrm{15 - 6 + 3 = 9 + 3 = 12}\)
- Result: \(\mathrm{12b^2}\)
Answer: (C) \(\mathrm{12b^2}\)
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak SIMPLIFY execution: Making sign errors when computing \(\mathrm{15 - 6 + 3}\)
Students might mishandle the signs and compute:
- \(\mathrm{15 - 6 - 3 = 6}\), leading them to select Choice (A) \(\mathrm{(6b^2)}\)
- \(\mathrm{15 + 6 + 3 = 24}\) (not an option, causing confusion)
- \(\mathrm{15 + 6 - 3 = 18}\), leading them to select Choice (D) \(\mathrm{(18b^2)}\)
Second Most Common Error:
Incomplete SIMPLIFY process: Stopping partway through the calculation
A student might compute \(\mathrm{15 - 6 = 9}\) and forget about the "\(\mathrm{+ 3b^2}\)" term entirely, leading them to select Choice (B) \(\mathrm{(9b^2)}\).
The Bottom Line:
This problem tests careful arithmetic with signed numbers. The algebra concept is straightforward, but execution errors in basic arithmetic cause most mistakes.
Answer Choices Explained
A
\(6\mathrm{b}^2\)
B
\(9\mathrm{b}^2\)
C
\(12\mathrm{b}^2\)
D
\(18\mathrm{b}^2\)
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