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Question:2/3x + 1/2y = 5/6 + 1/3x3/4y - 1/2 = kx + 1/4yIn the given system of equations, k is...

GMAT Algebra : (Alg) Questions

Source: Prism
Algebra
Systems of 2 linear equations in 2 variables
HARD
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Notes
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Question:

\(\frac{2}{3}\mathrm{x} + \frac{1}{2}\mathrm{y} = \frac{5}{6} + \frac{1}{3}\mathrm{x}\)

\(\frac{3}{4}\mathrm{y} - \frac{1}{2} = \mathrm{kx} + \frac{1}{4}\mathrm{y}\)


In the given system of equations, \(\mathrm{k}\) is a constant. If the system has no solution, what is the value of \(\mathrm{k}\)?


Express your answer as a fraction in lowest terms.

A

\(-3\)

B

\(-\frac{2}{3}\)

C

\(-\frac{1}{2}\)

D

\(-\frac{1}{3}\)

Solution

1. TRANSLATE the problem information

  • Given: System of equations with parameter k
  • Find: Value of k that makes system have no solution
  • Key insight: "No solution" is a specific mathematical condition

2. SIMPLIFY both equations to standard form

  • First equation: \(\frac{2}{3}\mathrm{x} + \frac{1}{2}\mathrm{y} = \frac{5}{6} + \frac{1}{3}\mathrm{x}\)
    • Move x terms to left: \((\frac{2}{3} - \frac{1}{3})\mathrm{x} + \frac{1}{2}\mathrm{y} = \frac{5}{6}\)
    • Result: \(\frac{1}{3}\mathrm{x} + \frac{1}{2}\mathrm{y} = \frac{5}{6}\)
  • Second equation: \(\frac{3}{4}\mathrm{y} - \frac{1}{2} = \mathrm{kx} + \frac{1}{4}\mathrm{y}\)
    • Move y terms to left: \((\frac{3}{4} - \frac{1}{4})\mathrm{y} = \mathrm{kx} + \frac{1}{2}\)
    • Simplify: \(\frac{1}{2}\mathrm{y} = \mathrm{kx} + \frac{1}{2}\)
    • Rearrange: \(-\mathrm{kx} + \frac{1}{2}\mathrm{y} = \frac{1}{2}\)

3. INFER the condition for no solution

  • No solution occurs when equations represent parallel lines
  • Parallel lines: same slope, different y-intercepts
  • Need to convert to slope-intercept form: \(\mathrm{y} = \mathrm{mx} + \mathrm{b}\)

4. SIMPLIFY to slope-intercept form

  • Equation 1: \(\frac{1}{3}\mathrm{x} + \frac{1}{2}\mathrm{y} = \frac{5}{6}\)
    • Solve for y: \(\frac{1}{2}\mathrm{y} = -\frac{1}{3}\mathrm{x} + \frac{5}{6}\)
    • Multiply by 2: \(\mathrm{y} = -\frac{2}{3}\mathrm{x} + \frac{5}{3}\)
  • Equation 2: \(-\mathrm{kx} + \frac{1}{2}\mathrm{y} = \frac{1}{2}\)
    • Solve for y: \(\frac{1}{2}\mathrm{y} = \mathrm{kx} + \frac{1}{2}\)
    • Multiply by 2: \(\mathrm{y} = 2\mathrm{kx} + 1\)

5. APPLY CONSTRAINTS for parallel lines

  • For same slope: \(-\frac{2}{3} = 2\mathrm{k}\)
  • Solve: \(\mathrm{k} = -\frac{2}{3} \div 2 = -\frac{1}{3}\)
  • Verify different y-intercepts: \(\frac{5}{3} \neq 1\)

Answer: D) -1/3


Why Students Usually Falter on This Problem

Most Common Error Path:

Weak SIMPLIFY skill: Making fraction arithmetic errors when collecting like terms or converting between forms.

Students often struggle with operations like \((\frac{2}{3} - \frac{1}{3})\mathrm{x}\) or converting \(\frac{1}{2}\mathrm{y} = -\frac{1}{3}\mathrm{x} + \frac{5}{6}\) to slope-intercept form. A common mistake is getting \(\mathrm{y} = -\frac{1}{3}\mathrm{x} + \frac{5}{6}\) instead of \(\mathrm{y} = -\frac{2}{3}\mathrm{x} + \frac{5}{3}\), leading to the wrong slope comparison. This may lead them to select Choice B (-2/3) or get confused and guess.

Second Most Common Error:

Incomplete INFER reasoning: Understanding that no solution means something special, but not connecting it to the parallel lines condition.

Some students recognize they need equal slopes but forget to verify different y-intercepts, or they set the entire equations equal instead of just the slopes. This leads to confusion and guessing among the available choices.

The Bottom Line:

This problem combines algebraic manipulation with systems theory. Success requires both technical fraction skills and conceptual understanding of what "no solution" means geometrically.

Answer Choices Explained
A

\(-3\)

B

\(-\frac{2}{3}\)

C

\(-\frac{1}{2}\)

D

\(-\frac{1}{3}\)

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