At a conference, a coordinator schedules s short talks, each lasting 20 minutes, and l long talks, each lasting 50...
GMAT Algebra : (Alg) Questions
At a conference, a coordinator schedules \(\mathrm{s}\) short talks, each lasting \(\mathrm{20}\) minutes, and \(\mathrm{l}\) long talks, each lasting \(\mathrm{50}\) minutes. The total scheduled time for all talks is \(\mathrm{440}\) minutes. Which equation represents this situation?
\(\mathrm{s + l = 440}\)
\(\mathrm{20s + l = 440}\)
\(\mathrm{20s + 50l = 440}\)
\(\mathrm{s + 50l = 440}\)
1. TRANSLATE the problem information
- Given information:
- \(\mathrm{s}\) = number of short talks (unknown)
- \(\mathrm{l}\) = number of long talks (unknown)
- Each short talk = \(\mathrm{20}\) minutes
- Each long talk = \(\mathrm{50}\) minutes
- Total scheduled time = \(\mathrm{440}\) minutes
2. INFER how to find total time
- The total time comes from adding contributions of both talk types
- Each talk type contributes: (number of talks) × (time per talk)
- So we need: (short talk time) + (long talk time) = total time
3. TRANSLATE each contribution into math
- Short talks contribute: \(\mathrm{s}\) talks × \(\mathrm{20}\) minutes each = \(\mathrm{20s}\) minutes
- Long talks contribute: \(\mathrm{l}\) talks × \(\mathrm{50}\) minutes each = \(\mathrm{50l}\) minutes
- Total equation: \(\mathrm{20s + 50l = 440}\)
Answer: C
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak TRANSLATE skill: Students don't recognize that they need to multiply the number of talks by the duration per talk.
Instead, they might think the equation should just count the talks themselves: \(\mathrm{s + l = 440}\). This treats the variables as if they represent minutes rather than number of talks, ignoring that different talks have different durations.
This may lead them to select Choice A (\(\mathrm{s + l = 440}\)).
Second Most Common Error:
Incomplete TRANSLATE reasoning: Students correctly identify that short talks contribute \(\mathrm{20s}\) minutes, but incorrectly think long talks just contribute \(\mathrm{l}\) minutes instead of \(\mathrm{50l}\) minutes.
This creates the equation \(\mathrm{20s + l = 440}\), mixing time units (\(\mathrm{20s}\) in minutes) with count units (\(\mathrm{l}\) as number of talks).
This may lead them to select Choice B (\(\mathrm{20s + l = 440}\)).
The Bottom Line:
This problem requires careful attention to units and what each variable represents. Success depends on systematically translating each part: "\(\mathrm{s}\) short talks at \(\mathrm{20}\) minutes each" becomes "\(\mathrm{20s}\) minutes total from short talks."
\(\mathrm{s + l = 440}\)
\(\mathrm{20s + l = 440}\)
\(\mathrm{20s + 50l = 440}\)
\(\mathrm{s + 50l = 440}\)