In 2020, a biologist estimated that there were 4,500 individuals of a certain fish species in a lake. The population...
GMAT Advanced Math : (Adv_Math) Questions
In 2020, a biologist estimated that there were 4,500 individuals of a certain fish species in a lake. The population is projected to decrease by \(15\%\) every 6 months. The function \(\mathrm{P}\) models the estimated population \(\mathrm{t}\) years after 2020. Which equation defines \(\mathrm{P}\)?
- \(\mathrm{P(t)} = 4500(0.85)^{\mathrm{t}/2}\)
- \(\mathrm{P(t)} = 4500(0.15)^{\mathrm{t}/2}\)
- \(\mathrm{P(t)} = 4500(0.85)^{2\mathrm{t}}\)
- \(\mathrm{P(t)} = 4500(1.15)^{2\mathrm{t}}\)
1. TRANSLATE the problem information
- Given information:
- Initial population in 2020: 4,500 fish
- Population decreases by 15% every 6 months
- t represents years after 2020
- Need function P(t) for population after t years
2. INFER the mathematical model needed
- This describes exponential decay, which follows the pattern: \(\mathrm{P(t) = a(b)^x}\)
- Need to identify: initial value (a), decay factor (b), and number of periods (x)
3. TRANSLATE each component
- Initial value: \(\mathrm{a = 4{,}500}\) (the starting population)
- Decay factor: "decreases by 15%" means 85% remains each period
- \(\mathrm{b = 1 - 0.15 = 0.85}\)
- Time periods: This is where it gets tricky!
- Decay happens every 6 months
- But t is measured in years
- In 1 year, there are 2 six-month periods
- In t years, there are \(\mathrm{2t}\) six-month periods
4. SIMPLIFY to final form
- Substitute into exponential model:
\(\mathrm{P(t) = 4500(0.85)^{2t}}\)
- This matches choice C
Answer: C. \(\mathrm{P(t) = 4500(0.85)^{2t}}\)
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak TRANSLATE skill: Confusing the relationship between years and 6-month periods, leading to the wrong exponent.
Students often think: "If t is in years and decay happens every 6 months, then in t years there are \(\mathrm{t/2}\) periods." This backwards reasoning comes from thinking "6 months is half a year, so I divide by 2."
This leads them to select Choice A: \(\mathrm{P(t) = 4500(0.85)^{t/2}}\)
Second Most Common Error:
Conceptual confusion about decay factors: Using 0.15 instead of 0.85 as the decay factor.
Students mistakenly think the decay factor should be the percentage that's lost (15%) rather than the percentage that remains (85%). This fundamental misunderstanding of how exponential decay works causes them to use the wrong base.
This may lead them to select Choice B: \(\mathrm{P(t) = 4500(0.15)^{t/2}}\) (combining both errors)
The Bottom Line:
The key challenge is correctly TRANSLATING between different time units while understanding that exponential decay uses the "remaining factor" (0.85), not the "lost factor" (0.15).