The expression \((2\mathrm{x} - 3)(\mathrm{x} + \mathrm{k}) + \mathrm{j}\) equals 2x^2 + px + q, where j, k, p, and...
GMAT Advanced Math : (Adv_Math) Questions
The expression \((2\mathrm{x} - 3)(\mathrm{x} + \mathrm{k}) + \mathrm{j}\) equals \(2\mathrm{x}^2 + \mathrm{px} + \mathrm{q}\), where j, k, p, and q are integers. If \(\mathrm{k} = 5\) and \(\mathrm{j} = -4\), what is the value of \(\mathrm{p} + \mathrm{q}\)?
\(-19\)
\(-12\)
\(-7\)
\(7\)
\(26\)
1. TRANSLATE the problem information
- Given information:
- \((2x - 3)(x + k) + j\) equals \(2x^2 + px + q\)
- \(k = 5\) and \(j = -4\)
- Need to find \(p + q\)
- What this tells us: We need to expand the left side, then match coefficients with the right side.
2. TRANSLATE by substituting known values
- Replace \(k\) with \(5\) and \(j\) with \(-4\):
\((2x - 3)(x + 5) + (-4) = 2x^2 + px + q\)
3. SIMPLIFY by expanding the binomial
- Use FOIL to expand \((2x - 3)(x + 5)\):
- First: \(2x \cdot x = 2x^2\)
- Outer: \(2x \cdot 5 = 10x\)
- Inner: \(-3 \cdot x = -3x\)
- Last: \(-3 \cdot 5 = -15\)
- Combine:
\(2x^2 + 10x - 3x - 15 = 2x^2 + 7x - 15\)
4. SIMPLIFY by adding the constant term
- Add \(j = -4\):
\(2x^2 + 7x - 15 + (-4) = 2x^2 + 7x - 19\)
5. INFER by comparing coefficients
- We have: \(2x^2 + 7x - 19 = 2x^2 + px + q\)
- Comparing coefficients:
- \(x\) coefficient: \(7 = p\), so \(p = 7\)
- Constant term: \(-19 = q\), so \(q = -19\)
6. SIMPLIFY the final calculation
- \(p + q = 7 + (-19) = -12\)
Answer: B. -12
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak SIMPLIFY execution: Students make arithmetic errors during the FOIL expansion or when combining like terms.
For example, they might calculate:
- \((2x - 3)(x + 5) = 2x^2 + 10x - 3x - 15 = 2x^2 + 13x - 15\) (adding \(10x + 3x\) instead of \(10x - 3x\))
This leads to \(p = 13\) and \(q = -19\), giving \(p + q = -6\). Since \(-6\) isn't among the choices, this causes confusion and guessing.
Second Most Common Error:
Poor TRANSLATE reasoning: Students forget to add \(j = -4\) to their expanded expression.
They correctly expand \((2x - 3)(x + 5) = 2x^2 + 7x - 15\), but then compare this directly to \(2x^2 + px + q\), getting \(p = 7\) and \(q = -15\). This gives \(p + q = -8\), which also isn't among the choices, leading to random selection.
The Bottom Line:
This problem tests whether students can systematically work through polynomial expansion while keeping track of all given values. The key insight is that every piece of given information (\(k = 5\) AND \(j = -4\)) must be incorporated into the final expression before comparing coefficients.
\(-19\)
\(-12\)
\(-7\)
\(7\)
\(26\)