Question:The variables x and y satisfy the system of equations:2x - 3y = 1/24x + y = 13/2What is the...
GMAT Algebra : (Alg) Questions
The variables \(\mathrm{x}\) and \(\mathrm{y}\) satisfy the system of equations:
\(\mathrm{2x - 3y = \frac{1}{2}}\)
\(\mathrm{4x + y = \frac{13}{2}}\)
What is the value of \(\mathrm{y}\)?
1. TRANSLATE the problem information
- Given system:
- \(2\mathrm{x} - 3\mathrm{y} = \frac{1}{2}\)
- \(4\mathrm{x} + \mathrm{y} = \frac{13}{2}\)
- Need to find: the value of y
2. INFER the solution approach
- Since the second equation has y with coefficient 1, it's easier to solve for y in terms of x
- Use substitution method: solve the simpler equation for one variable, then substitute
3. SIMPLIFY to isolate y from the second equation
From \(4\mathrm{x} + \mathrm{y} = \frac{13}{2}\), we get:
\(\mathrm{y} = \frac{13}{2} - 4\mathrm{x}\)
4. SIMPLIFY by substituting into the first equation
Substitute \(\mathrm{y} = \frac{13}{2} - 4\mathrm{x}\) into \(2\mathrm{x} - 3\mathrm{y} = \frac{1}{2}\):
\(2\mathrm{x} - 3(\frac{13}{2} - 4\mathrm{x}) = \frac{1}{2}\)
5. SIMPLIFY using the distributive property
\(2\mathrm{x} - 3(\frac{13}{2}) - 3(-4\mathrm{x}) = \frac{1}{2}\)
\(2\mathrm{x} - \frac{39}{2} + 12\mathrm{x} = \frac{1}{2}\)
\(14\mathrm{x} - \frac{39}{2} = \frac{1}{2}\)
6. SIMPLIFY to solve for x
\(14\mathrm{x} = \frac{1}{2} + \frac{39}{2} = \frac{40}{2} = 20\)
\(\mathrm{x} = \frac{20}{14} = \frac{10}{7}\)
7. SIMPLIFY to find y by substitution
\(\mathrm{y} = \frac{13}{2} - 4(\frac{10}{7})\)
\(\mathrm{y} = \frac{13}{2} - \frac{40}{7}\)
Convert to common denominator:
\(\mathrm{y} = \frac{91}{14} - \frac{80}{14} = \frac{11}{14}\)
Answer: \(\frac{11}{14}\)
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak SIMPLIFY skill: Sign errors when distributing the negative coefficient
When expanding \(2\mathrm{x} - 3(\frac{13}{2} - 4\mathrm{x})\), students often make the error:
\(2\mathrm{x} - \frac{39}{2} - 12\mathrm{x} = \frac{1}{2}\) (forgetting that \(-3 \times (-4\mathrm{x}) = +12\mathrm{x}\))
This leads to: \(-10\mathrm{x} = \frac{1}{2} + \frac{39}{2} = 20\), so \(\mathrm{x} = -2\)
Then \(\mathrm{y} = \frac{13}{2} - 4(-2) = \frac{13}{2} + 8 = \frac{29}{2}\)
This type of error leads to confusion as verification fails, causing students to get stuck and guess.
Second Most Common Error:
Weak SIMPLIFY skill: Fraction arithmetic errors when finding common denominators
Students might correctly get to \(\mathrm{y} = \frac{13}{2} - \frac{40}{7}\) but then make errors like:
- Using wrong common denominator (7 instead of 14)
- Arithmetic errors: \(\frac{91}{14} - \frac{80}{14} = \frac{71}{14}\) instead of \(\frac{11}{14}\)
These calculation errors produce incorrect final answers that don't verify with the original system.
The Bottom Line:
This problem tests careful algebraic manipulation with fractions. Success requires methodical application of the distributive property and precise fraction arithmetic—areas where small errors compound into completely wrong answers.