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2x + 3y = 66x + ky = 9In the given system of equations, k is a constant. If the...

GMAT Algebra : (Alg) Questions

Source: Prism
Algebra
Systems of 2 linear equations in 2 variables
HARD
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Notes
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\(2\mathrm{x} + 3\mathrm{y} = 6\)

\(6\mathrm{x} + \mathrm{k}\mathrm{y} = 9\)

In the given system of equations, \(\mathrm{k}\) is a constant. If the system has no solution, what is the value of \(\mathrm{k}\)?

A
\(\mathrm{-9}\)
B
\(\mathrm{0}\)
C
\(\mathrm{9}\)
D
\(\mathrm{18}\)
Solution

1. INFER what no solution means for a system

  • A system has no solution when the equations represent parallel lines that never intersect
  • This happens when:
    • The coefficients of x and y are proportional (same slope)
    • BUT the constant terms don't follow the same proportion (different y-intercepts)

2. TRANSLATE the given information

  • Given system:
    • \(\mathrm{2x + 3y = 6}\)
    • \(\mathrm{6x + ky = 9}\)
  • We need to find k that makes this system have no solution

3. INFER the condition for proportional coefficients

  • For the lines to be parallel, the ratios of corresponding coefficients must be equal:
    • x-coefficient ratio: \(\mathrm{\frac{2}{6} = \frac{1}{3}}\)
    • y-coefficient ratio: \(\mathrm{\frac{3}{k}}\)
  • Therefore: \(\mathrm{\frac{3}{k} = \frac{1}{3}}\)

4. SIMPLIFY to solve for k

  • From \(\mathrm{\frac{3}{k} = \frac{1}{3}}\), cross multiply:

\(\mathrm{3 \times 3 = k \times 1}\)

\(\mathrm{9 = k}\)

  • So \(\mathrm{k = 9}\)

5. INFER verification of no solution

  • With \(\mathrm{k = 9}\), our system becomes:
    • \(\mathrm{2x + 3y = 6}\)
    • \(\mathrm{6x + 9y = 9}\)
  • Divide the second equation by 3: \(\mathrm{2x + 3y = 3}\)
  • Now we have: \(\mathrm{2x + 3y = 6}\) AND \(\mathrm{2x + 3y = 3}\)
  • This is impossible - the same expression cannot equal two different numbers!

Answer: C) 9




Why Students Usually Falter on This Problem

Most Common Error Path:

Weak INFER skill: Students confuse no solution with infinitely many solutions

They think both conditions require proportional coefficients, so they set up \(\mathrm{\frac{2}{6} = \frac{3}{k} = \frac{6}{9}}\), leading to \(\mathrm{\frac{3}{k} = \frac{2}{3}}\), which gives \(\mathrm{k = \frac{9}{2} = 4.5}\). Since 4.5 isn't among the choices, this leads to confusion and guessing.

Second Most Common Error:

Incomplete INFER reasoning: Students correctly find \(\mathrm{k = 9}\) but don't verify it actually creates no solution

They might worry they made an error since they didn't check their work, leading them to second-guess and potentially select Choice A (-9) by incorrectly thinking about sign relationships, or Choice B (0) assuming a special case.

The Bottom Line:

The key insight is distinguishing between no solution (parallel lines) and infinitely many solutions (identical lines). No solution requires coefficients to be proportional BUT constants to break that same proportion.

Answer Choices Explained
A
\(\mathrm{-9}\)
B
\(\mathrm{0}\)
C
\(\mathrm{9}\)
D
\(\mathrm{18}\)
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