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Which expression is equivalent to 3/(x^(2) + x) - 1/(x + 2), where x neq 0, x neq -1, and...

GMAT Advanced Math : (Adv_Math) Questions

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Advanced Math
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Which expression is equivalent to \(\frac{3}{x^{2} + x} - \frac{1}{x + 2}\), where \(x \neq 0\), \(x \neq -1\), and \(x \neq -2\)?

A
\(\frac{2}{\mathrm{x}(\mathrm{x} + 2)}\)
B
\(\frac{-\mathrm{x}^2 + 2\mathrm{x} + 6}{\mathrm{x}(\mathrm{x} + 1)}\)
C
\(\frac{-\mathrm{x}^2 + 2\mathrm{x} + 6}{(\mathrm{x} + 1)(\mathrm{x} + 2)}\)
D
\(\frac{-\mathrm{x}^2 + 2\mathrm{x} + 6}{\mathrm{x}(\mathrm{x} + 1)(\mathrm{x} + 2)}\)
Solution

1. INFER the approach needed

  • When subtracting rational expressions, we need a common denominator
  • But first, let's see if we can factor any denominators to make this easier

2. SIMPLIFY by factoring the first denominator

  • Factor \(x^2 + x\): Look for common factors
  • \(x^2 + x = x(x + 1)\)
  • Now our expression is: \(\frac{3}{x(x + 1)} - \frac{1}{x + 2}\)

3. INFER the common denominator strategy

  • First denominator: \(x(x + 1)\)
  • Second denominator: \((x + 2)\)
  • These share no common factors, so LCD = \(x(x + 1)(x + 2)\)

4. SIMPLIFY by rewriting with common denominators

\(\frac{3}{x(x + 1)} - \frac{1}{x + 2} = \frac{3(x + 2)}{x(x + 1)(x + 2)} - \frac{x(x + 1)}{x(x + 1)(x + 2)}\)

5. SIMPLIFY by subtracting the fractions

\(= \frac{3(x + 2) - x(x + 1)}{x(x + 1)(x + 2)}\)

6. SIMPLIFY the numerator through expansion

  • Expand \(3(x + 2) = 3x + 6\)
  • Expand \(x(x + 1) = x^2 + x\)
  • So: \(3(x + 2) - x(x + 1) = 3x + 6 - x^2 - x = -x^2 + 2x + 6\)

Answer: D \(\frac{-x^2 + 2x + 6}{x(x + 1)(x + 2)}\)


Why Students Usually Falter on This Problem

Most Common Error Path:

Poor SIMPLIFY execution: Students correctly identify the need for a common denominator but make errors when expanding the numerator.

A typical mistake: \(3(x + 2) - x(x + 1) = 3x + 6 - x^2 + x\) (forgetting the negative sign distributes)

This gives numerator \(-x^2 + 4x + 6\) instead of \(-x^2 + 2x + 6\), leading to confusion and guessing among the answer choices.

Second Most Common Error:

Incomplete INFER reasoning about common denominators: Students find a common denominator but miss including all factors.

They might use \(x(x + 1)\) or \((x + 1)(x + 2)\) as the LCD instead of the full \(x(x + 1)(x + 2)\).

This may lead them to select Choice B \(\frac{-x^2 + 2x + 6}{x(x + 1)}\) or Choice C \(\frac{-x^2 + 2x + 6}{(x + 1)(x + 2)}\).

The Bottom Line:

This problem tests systematic algebraic manipulation - students must execute multiple SIMPLIFY steps flawlessly while maintaining the correct strategy throughout.

Answer Choices Explained
A
\(\frac{2}{\mathrm{x}(\mathrm{x} + 2)}\)
B
\(\frac{-\mathrm{x}^2 + 2\mathrm{x} + 6}{\mathrm{x}(\mathrm{x} + 1)}\)
C
\(\frac{-\mathrm{x}^2 + 2\mathrm{x} + 6}{(\mathrm{x} + 1)(\mathrm{x} + 2)}\)
D
\(\frac{-\mathrm{x}^2 + 2\mathrm{x} + 6}{\mathrm{x}(\mathrm{x} + 1)(\mathrm{x} + 2)}\)
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