Which expression is equivalent to 3/(x-5) - (2x+1)/(x^2-25)?
GMAT Advanced Math : (Adv_Math) Questions
Which expression is equivalent to \(\frac{3}{x-5} - \frac{2x+1}{x^2-25}\)?
1. TRANSLATE the problem information
- Given: \(\frac{3}{\mathrm{x}-5} - \frac{2\mathrm{x}+1}{\mathrm{x}^2-25}\)
- Goal: Find an equivalent single rational expression
2. INFER the solution strategy
- To subtract rational expressions, we need a common denominator
- Notice that \(\mathrm{x}^2-25\) looks like a difference of squares: \(\mathrm{x}^2-25 = (\mathrm{x}-5)(\mathrm{x}+5)\)
- This means the LCD is \(\mathrm{x}^2-25\)
3. SIMPLIFY by converting to the common denominator
- The second fraction already has denominator \(\mathrm{x}^2-25\)
- Convert the first fraction: \(\frac{3}{\mathrm{x}-5} \times \frac{\mathrm{x}+5}{\mathrm{x}+5} = \frac{3\mathrm{x}+15}{\mathrm{x}^2-25}\)
4. SIMPLIFY by combining the fractions
- Now we have: \(\frac{3\mathrm{x}+15}{\mathrm{x}^2-25} - \frac{2\mathrm{x}+1}{\mathrm{x}^2-25}\)
- Combine numerators: \(\frac{3\mathrm{x}+15 - (2\mathrm{x}+1)}{\mathrm{x}^2-25}\)
- Distribute the negative: \(\frac{3\mathrm{x}+15 - 2\mathrm{x} - 1}{\mathrm{x}^2-25}\)
- Combine like terms: \(\frac{\mathrm{x}+14}{\mathrm{x}^2-25}\)
Answer: B. \(\frac{\mathrm{x}+14}{\mathrm{x}^2-25}\)
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak SIMPLIFY execution: Students forget to distribute the negative sign to both terms in \((2\mathrm{x}+1)\)
They write: \(3\mathrm{x}+15 - 2\mathrm{x}+1\) instead of \(3\mathrm{x}+15 - 2\mathrm{x} - 1\)
This gives them \(\frac{2\mathrm{x}+16}{\mathrm{x}^2-25}\)
This may lead them to select Choice C \((\frac{2\mathrm{x}+16}{\mathrm{x}^2-25})\)
Second Most Common Error:
Missing INFER insight: Students don't recognize that \(\mathrm{x}^2-25\) factors as \((\mathrm{x}-5)(\mathrm{x}+5)\)
Without this insight, they struggle to find the common denominator and may attempt incorrect algebraic manipulations or give up and guess randomly.
The Bottom Line:
This problem tests both pattern recognition (spotting the difference of squares) and careful algebraic execution (proper sign distribution). Success requires methodical attention to detail in multi-step simplification.