Consider the system of equations below:3x + ky = 156x - 8y = k + 10For what value of k...
GMAT Algebra : (Alg) Questions
Consider the system of equations below:
\(3\mathrm{x} + \mathrm{k}\mathrm{y} = 15\)
\(6\mathrm{x} - 8\mathrm{y} = \mathrm{k} + 10\)
For what value of k does this system have no solution?
Enter your answer as an integer.
1. TRANSLATE the problem requirement
- Given: System of equations with parameter k
- Find: Value of k that makes the system have no solution
- Key insight: "No solution" is a specific mathematical condition
2. INFER what "no solution" means geometrically
- A system has no solution when the equations represent parallel lines
- Parallel lines: same slope, different y-intercepts
- This creates an inconsistent system (contradictory equations)
3. INFER the coefficient ratio strategy
- For parallel lines, coefficient ratios must be equal
- System: \(\mathrm{3x + ky = 15}\) and \(\mathrm{6x - 8y = k + 10}\)
- x-coefficient ratio: \(\mathrm{\frac{3}{6} = \frac{1}{2}}\)
- y-coefficient ratio must equal: \(\mathrm{\frac{k}{-8} = \frac{1}{2}}\)
4. SIMPLIFY to solve for k
- Set up the proportion: \(\mathrm{\frac{k}{-8} = \frac{1}{2}}\)
- Cross multiply: \(\mathrm{k = (-8) \times \frac{1}{2}}\)
- Calculate: \(\mathrm{k = -4}\)
5. INFER verification is needed
- Substitute \(\mathrm{k = -4}\) back into original system
- Equation 1: \(\mathrm{3x - 4y = 15}\)
- Equation 2: \(\mathrm{6x - 8y = 6}\), which simplifies to \(\mathrm{3x - 4y = 3}\)
- Since \(\mathrm{3x - 4y}\) cannot equal both 15 and 3, system is inconsistent ✓
Answer: -4
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak INFER skill: Students don't connect "no solution" with the parallel lines concept. They might try to solve the system directly by elimination or substitution, get confused when variables cancel out leaving a false statement like \(\mathrm{15 = 3}\), but don't understand this means they need to work backwards to find what k value caused this.
This leads to confusion and guessing rather than systematic solution.
Second Most Common Error:
Poor SIMPLIFY execution: Students correctly identify the need for coefficient ratios but make sign errors when solving \(\mathrm{\frac{k}{-8} = \frac{1}{2}}\). They might forget the negative sign and calculate \(\mathrm{k = 4}\) instead of \(\mathrm{k = -4}\), or incorrectly cross multiply.
This may lead them to select k = 4 if that's an available option.
The Bottom Line:
This problem requires students to think backwards - instead of solving a system, they must determine what parameter value prevents a solution from existing. The key insight is recognizing that parallel lines (equal coefficient ratios) create the "no solution" condition.