prismlearning.academy Logo
NEUR
N

Consider the system of equations below:3x + ky = 156x - 8y = k + 10For what value of k...

GMAT Algebra : (Alg) Questions

Source: Prism
Algebra
Systems of 2 linear equations in 2 variables
HARD
...
...
Notes
Post a Query

Consider the system of equations below:

\(3\mathrm{x} + \mathrm{k}\mathrm{y} = 15\)

\(6\mathrm{x} - 8\mathrm{y} = \mathrm{k} + 10\)

For what value of k does this system have no solution?

Enter your answer as an integer.

Enter your answer here
Solution

1. TRANSLATE the problem requirement

  • Given: System of equations with parameter k
  • Find: Value of k that makes the system have no solution
  • Key insight: "No solution" is a specific mathematical condition

2. INFER what "no solution" means geometrically

  • A system has no solution when the equations represent parallel lines
  • Parallel lines: same slope, different y-intercepts
  • This creates an inconsistent system (contradictory equations)

3. INFER the coefficient ratio strategy

  • For parallel lines, coefficient ratios must be equal
  • System: \(\mathrm{3x + ky = 15}\) and \(\mathrm{6x - 8y = k + 10}\)
  • x-coefficient ratio: \(\mathrm{\frac{3}{6} = \frac{1}{2}}\)
  • y-coefficient ratio must equal: \(\mathrm{\frac{k}{-8} = \frac{1}{2}}\)

4. SIMPLIFY to solve for k

  • Set up the proportion: \(\mathrm{\frac{k}{-8} = \frac{1}{2}}\)
  • Cross multiply: \(\mathrm{k = (-8) \times \frac{1}{2}}\)
  • Calculate: \(\mathrm{k = -4}\)

5. INFER verification is needed

  • Substitute \(\mathrm{k = -4}\) back into original system
  • Equation 1: \(\mathrm{3x - 4y = 15}\)
  • Equation 2: \(\mathrm{6x - 8y = 6}\), which simplifies to \(\mathrm{3x - 4y = 3}\)
  • Since \(\mathrm{3x - 4y}\) cannot equal both 15 and 3, system is inconsistent ✓

Answer: -4


Why Students Usually Falter on This Problem

Most Common Error Path:

Weak INFER skill: Students don't connect "no solution" with the parallel lines concept. They might try to solve the system directly by elimination or substitution, get confused when variables cancel out leaving a false statement like \(\mathrm{15 = 3}\), but don't understand this means they need to work backwards to find what k value caused this.

This leads to confusion and guessing rather than systematic solution.

Second Most Common Error:

Poor SIMPLIFY execution: Students correctly identify the need for coefficient ratios but make sign errors when solving \(\mathrm{\frac{k}{-8} = \frac{1}{2}}\). They might forget the negative sign and calculate \(\mathrm{k = 4}\) instead of \(\mathrm{k = -4}\), or incorrectly cross multiply.

This may lead them to select k = 4 if that's an available option.

The Bottom Line:

This problem requires students to think backwards - instead of solving a system, they must determine what parameter value prevents a solution from existing. The key insight is recognizing that parallel lines (equal coefficient ratios) create the "no solution" condition.

Rate this Solution
Tell us what you think about this solution
...
...
Forum Discussions
Start a new discussion
Post
Load More
Similar Questions
Finding similar questions...
Previous Attempts
Loading attempts...
Similar Questions
Finding similar questions...
Parallel Question Generator
Create AI-generated questions with similar patterns to master this question type.