Which expression is equivalent to 5psqrt(p) + 15p/(sqrt(p)), where p is a positive number?20p20psqrt(p)\(5(\mathrm{p}+3)\sqrt{\mathrm{p}}\)\(\frac{5\m...
GMAT Advanced Math : (Adv_Math) Questions
Which expression is equivalent to \(5\mathrm{p}\sqrt{\mathrm{p}} + \frac{15\mathrm{p}}{\sqrt{\mathrm{p}}}\), where \(\mathrm{p}\) is a positive number?
- \(20\mathrm{p}\)
- \(20\mathrm{p}\sqrt{\mathrm{p}}\)
- \(5(\mathrm{p}+3)\sqrt{\mathrm{p}}\)
- \(\frac{5\mathrm{p}(\mathrm{p}^2+3)}{\sqrt{\mathrm{p}}}\)
1. TRANSLATE the problem information
- Given expression: \(5p\sqrt{p} + \frac{15p}{\sqrt{p}}\)
- Need to find equivalent expression from the choices
2. INFER the approach needed
- The second term \(\frac{15p}{\sqrt{p}}\) has a radical in the denominator - this suggests we should convert it to have radicals in the numerator instead
- Once both terms have similar radical forms, we can likely factor them
3. SIMPLIFY the second term using exponent rules
- Convert to exponential form: \(\frac{15p}{\sqrt{p}} = \frac{15p^1}{p^{1/2}}\)
- Apply exponent rule \(\frac{a^m}{a^n} = a^{m-n}\): \(15p^{1-1/2} = 15p^{1/2}\)
- Convert back to radical form: \(15p^{1/2} = 15\sqrt{p}\)
4. SIMPLIFY by substituting back
- Original expression becomes: \(5p\sqrt{p} + 15\sqrt{p}\)
- Now both terms contain \(\sqrt{p}\), making factoring possible
5. INFER the factoring strategy and SIMPLIFY
- Both terms have \(5\sqrt{p}\) as a common factor
- \(5p\sqrt{p} = 5\sqrt{p} \cdot p\) and \(15\sqrt{p} = 5\sqrt{p} \cdot 3\)
- Factor out \(5\sqrt{p}\): \(5\sqrt{p}(p + 3)\)
- Rewrite in standard form: \(5(p + 3)\sqrt{p}\)
Answer: C
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak SIMPLIFY skills: Incorrectly handling the division \(\frac{15p}{\sqrt{p}}\)
Students often struggle with dividing by radicals and may make errors like:
- Thinking \(\frac{15p}{\sqrt{p}} = \frac{15p}{p} = 15\) (ignoring the radical)
- Or trying \(\frac{15p}{\sqrt{p}} = \frac{15\sqrt{p}}{p}\) (incorrect radical manipulation)
This leads to wrong intermediate expressions that don't match any answer choice, causing confusion and guessing.
Second Most Common Error:
Poor INFER reasoning about factoring: After correctly getting \(5p\sqrt{p} + 15\sqrt{p}\), not recognizing the common factor
Students see the two different-looking terms \(5p\sqrt{p}\) and \(15\sqrt{p}\) and may think they can't be combined, or attempt to add them incorrectly (like \(5p\sqrt{p} + 15\sqrt{p} = 20p\sqrt{p}\)).
This may lead them to select Choice B (\(20p\sqrt{p}\)).
The Bottom Line:
This problem tests whether students can confidently manipulate expressions with radicals using exponent rules, then recognize factoring opportunities. The key insight is that dividing by a radical creates an opportunity to rewrite expressions in a form that reveals common factors.