Which expression is equivalent to \(5\mathrm{x}(2\mathrm{x} + 3) - 3\mathrm{x}(\mathrm{x} + 4)\)?
GMAT Advanced Math : (Adv_Math) Questions
Which expression is equivalent to \(5\mathrm{x}(2\mathrm{x} + 3) - 3\mathrm{x}(\mathrm{x} + 4)\)?
\(7\mathrm{x}^2 + 27\mathrm{x}\)
\(7\mathrm{x}^2 + 15\mathrm{x}\)
\(13\mathrm{x}^2 + 27\mathrm{x}\)
\(7\mathrm{x}^2 + 3\mathrm{x}\)
1. INFER the solution strategy
- Given: \(\mathrm{5x(2x + 3) - 3x(x + 4)}\)
- Strategy: We need to distribute each term first, then combine like terms
- This follows the order of operations - handle parentheses through distribution first
2. SIMPLIFY by distributing the first term
- Distribute 5x to each term in (2x + 3):
- \(\mathrm{5x \cdot 2x = 10x^2}\)
- \(\mathrm{5x \cdot 3 = 15x}\)
- Result: \(\mathrm{5x(2x + 3) = 10x^2 + 15x}\)
3. SIMPLIFY by distributing the second term
- Distribute -3x to each term in (x + 4):
- \(\mathrm{(-3x) \cdot x = -3x^2}\)
- \(\mathrm{(-3x) \cdot 4 = -12x}\)
- Result: \(\mathrm{-3x(x + 4) = -3x^2 - 12x}\)
4. SIMPLIFY by combining the distributed expressions
- Full expression: \(\mathrm{10x^2 + 15x - 3x^2 - 12x}\)
- Group like terms: \(\mathrm{(10x^2 - 3x^2) + (15x - 12x)}\)
5. SIMPLIFY by combining like terms
- x² terms: \(\mathrm{10x^2 - 3x^2 = 7x^2}\)
- x terms: \(\mathrm{15x - 12x = 3x}\)
- Final result: \(\mathrm{7x^2 + 3x}\)
Answer: D
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak SIMPLIFY execution with sign errors: Students correctly understand they need to distribute but make sign errors, particularly when handling the negative sign in front of 3x. They might treat \(\mathrm{-3x(x + 4)}\) as \(\mathrm{3x^2 + 12x}\) instead of \(\mathrm{-3x^2 - 12x}\).
When they calculate \(\mathrm{(10x^2 + 3x^2) + (15x + 12x)}\), they get \(\mathrm{13x^2 + 27x}\), leading them to select Choice C (\(\mathrm{13x^2 + 27x}\)).
Second Most Common Error:
Poor SIMPLIFY execution in combining like terms: Students distribute correctly but make arithmetic errors when combining like terms. They might calculate the x terms as \(\mathrm{15x + 12x = 27x}\) instead of \(\mathrm{15x - 12x = 3x}\), while correctly getting \(\mathrm{7x^2}\) for the x² coefficient.
This leads them to select Choice A (\(\mathrm{7x^2 + 27x}\)).
The Bottom Line:
This problem tests systematic algebraic manipulation skills. The key challenge is maintaining accuracy through multiple steps while carefully tracking positive and negative signs throughout the distribution and combination process.
\(7\mathrm{x}^2 + 27\mathrm{x}\)
\(7\mathrm{x}^2 + 15\mathrm{x}\)
\(13\mathrm{x}^2 + 27\mathrm{x}\)
\(7\mathrm{x}^2 + 3\mathrm{x}\)