If c is a constant, the polynomial 6x^2 - x - 15 is divisible by \(\mathrm{(2x + 3)}\). The result...
GMAT Advanced Math : (Adv_Math) Questions
If \(\mathrm{c}\) is a constant, the polynomial \(\mathrm{6x^2 - x - 15}\) is divisible by \(\mathrm{(2x + 3)}\). The result of this division is an expression of the form \(\mathrm{(3x - c)}\). What is the value of \(\mathrm{c}\)?
\(-5\)
\(1\)
\(3\)
\(5\)
\(15\)
1. TRANSLATE the problem statement
- Given information:
- Polynomial: \(6\mathrm{x}^2 - \mathrm{x} - 15\)
- Divisible by: \((2\mathrm{x} + 3)\)
- Quotient: \((3\mathrm{x} - \mathrm{c})\)
- Need to find: value of c
- What this tells us: Division means dividend = divisor × quotient
2. TRANSLATE the relationship into an equation
- Since \(6\mathrm{x}^2 - \mathrm{x} - 15 \div (2\mathrm{x} + 3) = (3\mathrm{x} - \mathrm{c})\), we can write:
\((2\mathrm{x} + 3)(3\mathrm{x} - \mathrm{c}) = 6\mathrm{x}^2 - \mathrm{x} - 15\)
3. SIMPLIFY by expanding the left side
- Use FOIL method on \((2\mathrm{x} + 3)(3\mathrm{x} - \mathrm{c})\):
- First terms: \((2\mathrm{x})(3\mathrm{x}) = 6\mathrm{x}^2\)
- Outer terms: \((2\mathrm{x})(-\mathrm{c}) = -2\mathrm{cx}\)
- Inner terms: \((3)(3\mathrm{x}) = 9\mathrm{x}\)
- Last terms: \((3)(-\mathrm{c}) = -3\mathrm{c}\)
- Combine: \(6\mathrm{x}^2 - 2\mathrm{cx} + 9\mathrm{x} - 3\mathrm{c} = 6\mathrm{x}^2 + (9 - 2\mathrm{c})\mathrm{x} - 3\mathrm{c}\)
4. INFER that coefficients must be equal
- Since \(6\mathrm{x}^2 + (9 - 2\mathrm{c})\mathrm{x} - 3\mathrm{c} = 6\mathrm{x}^2 - \mathrm{x} - 15\), the coefficients of like terms must match:
- x² coefficient: \(6 = 6\) ✓
- x coefficient: \(9 - 2\mathrm{c} = -1\)
- Constant term: \(-3\mathrm{c} = -15\)
5. SIMPLIFY to solve for c
- From constant terms: \(-3\mathrm{c} = -15\)
- Divide both sides by -3: \(\mathrm{c} = 5\)
- Verify with x terms: \(9 - 2(5) = 9 - 10 = -1\) ✓
Answer: D) 5
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak TRANSLATE skill: Students may not recognize that "divisible by \((2\mathrm{x} + 3)\) with quotient \((3\mathrm{x} - \mathrm{c})\)" means \((2\mathrm{x} + 3)(3\mathrm{x} - \mathrm{c})\) equals the original polynomial. Instead, they might try to perform long division directly or set up incorrect equations like \((2\mathrm{x} + 3) + (3\mathrm{x} - \mathrm{c}) = 6\mathrm{x}^2 - \mathrm{x} - 15\).
This leads to confusion and guessing among the answer choices.
Second Most Common Error:
Poor SIMPLIFY execution: Students correctly set up \((2\mathrm{x} + 3)(3\mathrm{x} - \mathrm{c}) = 6\mathrm{x}^2 - \mathrm{x} - 15\) but make algebraic errors when expanding, such as:
- Getting signs wrong: writing +2cx instead of -2cx
- Forgetting terms when using FOIL
- Making errors when combining like terms
This typically leads them to select Choice A (-5) or Choice B (1) based on their incorrect expansion.
The Bottom Line:
This problem requires students to translate a division concept into multiplication form and then execute careful algebraic manipulation. Students who rush through the FOIL expansion or don't fully understand the division-multiplication relationship will struggle to find the correct parameter value.
\(-5\)
\(1\)
\(3\)
\(5\)
\(15\)