For real numbers a and b, define a @ b = (3a - b)/4. What is the value of 6...
GMAT Algebra : (Alg) Questions
For real numbers a and b, define \(\mathrm{a @ b = \frac{3a - b}{4}}\). What is the value of \(\mathrm{6 @ 2}\)?
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1. TRANSLATE the problem information
- Given operation definition: \(\mathrm{a @ b = \frac{3a - b}{4}}\)
- Need to find: \(\mathrm{6 @ 2}\)
- This means we substitute \(\mathrm{a = 6}\) and \(\mathrm{b = 2}\) into the definition
2. TRANSLATE the specific calculation
- Replace \(\mathrm{a}\) with \(\mathrm{6}\) and \(\mathrm{b}\) with \(\mathrm{2}\) in the expression \(\mathrm{\frac{3a - b}{4}}\)
- This gives us: \(\mathrm{6 @ 2 = \frac{3(6) - 2}{4}}\)
3. SIMPLIFY using order of operations
- First, multiply inside the parentheses: \(\mathrm{3(6) = 18}\)
- Expression becomes: \(\mathrm{\frac{18 - 2}{4}}\)
- Next, subtract inside parentheses: \(\mathrm{18 - 2 = 16}\)
- Expression becomes: \(\mathrm{\frac{16}{4}}\)
- Finally, divide: \(\mathrm{16 ÷ 4 = 4}\)
Answer: B. 4
Why Students Usually Falter on This Problem
Most Common Error Path:
SIMPLIFY execution error: Students make arithmetic mistakes during calculation, most commonly getting \(\mathrm{18 - 2 = 20}\) instead of \(\mathrm{16}\).
When they calculate \(\mathrm{\frac{18 - 2}{4}}\) as \(\mathrm{\frac{20}{4}}\), they get \(\mathrm{\frac{20}{4} = 5}\).
This leads them to select Choice C (5).
Second Most Common Error:
TRANSLATE reasoning error: Students misread the operation definition as addition instead of subtraction, thinking \(\mathrm{a @ b = \frac{3a + b}{4}}\).
Using this incorrect definition: \(\mathrm{\frac{3(6) + 2}{4} = \frac{18 + 2}{4} = \frac{20}{4} = 5}\).
This also leads them to select Choice C (5).
The Bottom Line:
This problem tests careful attention to detail in both reading the definition accurately and executing basic arithmetic correctly. The key is methodical substitution followed by precise calculation.
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