Let the function g be defined as \(\mathrm{g(x) = \frac{|x - a| + 45}{3a}}\), where a is a positive constant....
GMAT Advanced Math : (Adv_Math) Questions
Let the function g be defined as \(\mathrm{g(x) = \frac{|x - a| + 45}{3a}}\), where a is a positive constant. If \(\mathrm{g(a) = 6}\), what is the value of \(\mathrm{g(10)}\)?
\(\mathrm{5.5}\)
\(\mathrm{6.0}\)
\(\mathrm{6.5}\)
\(\mathrm{7.0}\)
1. TRANSLATE the problem information
- Given information:
- Function: \(\mathrm{g(x) = \frac{|x - a| + 45}{3a}}\) where a is positive
- Condition: \(\mathrm{g(a) = 6}\)
- What we need to find: \(\mathrm{g(10)}\)
2. INFER the solution strategy
- Key insight: We can't evaluate \(\mathrm{g(10)}\) without knowing the value of 'a'
- Strategy: Use the condition \(\mathrm{g(a) = 6}\) to find 'a' first
- Critical recognition: When \(\mathrm{x = a}\), we have \(\mathrm{|a - a| = |0| = 0}\)
3. SIMPLIFY to find the parameter 'a'
- Substitute \(\mathrm{x = a}\) into the function:
\(\mathrm{g(a) = \frac{|a - a| + 45}{3a}}\)
\(\mathrm{= \frac{0 + 45}{3a}}\)
\(\mathrm{= \frac{45}{3a}}\)
\(\mathrm{= \frac{15}{a}}\)
- Set this equal to 6 and solve:
\(\mathrm{\frac{15}{a} = 6}\)
\(\mathrm{15 = 6a}\)
\(\mathrm{a = \frac{15}{6} = 2.5}\)
4. SIMPLIFY to evaluate g(10)
- Substitute \(\mathrm{x = 10}\) and \(\mathrm{a = 2.5}\):
\(\mathrm{g(10) = \frac{|10 - 2.5| + 45}{3 \times 2.5}}\)
\(\mathrm{g(10) = \frac{7.5 + 45}{7.5}}\)
\(\mathrm{g(10) = \frac{52.5}{7.5} = 7.0}\) (use calculator)
Answer: D. 7.0
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak INFER skill: Students don't recognize that \(\mathrm{|a - a| = 0}\), instead treating it as \(\mathrm{|a| - |a|}\) or leaving it unsimplified. They might write \(\mathrm{g(a) = \frac{|a - a| + 45}{3a}}\) and get confused about how to proceed, not realizing this simplifies to \(\mathrm{\frac{45}{3a}}\).
This leads to confusion and prevents them from finding the correct value of 'a', causing them to get stuck and guess among the answer choices.
Second Most Common Error:
Poor SIMPLIFY execution: Students correctly identify that \(\mathrm{a = 2.5}\) but make calculation errors when evaluating \(\mathrm{g(10)}\). Common mistakes include calculating \(\mathrm{|10 - 2.5|}\) as 12.5 instead of 7.5, or errors in computing \(\mathrm{\frac{52.5}{7.5}}\).
These arithmetic errors may lead them to select Choice B (6.0) or Choice C (6.5) instead of the correct answer.
The Bottom Line:
The key challenge is recognizing that finding the parameter 'a' is the essential first step, and that \(\mathrm{|a - a| = 0}\) is the breakthrough insight that makes this possible.
\(\mathrm{5.5}\)
\(\mathrm{6.0}\)
\(\mathrm{6.5}\)
\(\mathrm{7.0}\)