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A company opens an account with an initial balance of $5,000.00. The account earns 4% annual interest compounded semi-annually, and...

GMAT Advanced Math : (Adv_Math) Questions

Source: Prism
Advanced Math
Nonlinear functions
MEDIUM
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A company opens an account with an initial balance of \(\$5,000.00\). The account earns \(4\%\) annual interest compounded semi-annually, and no additional deposits or withdrawals are made. The account balance is given by an exponential function A, where \(\mathrm{A(t)}\) is the account balance, in dollars, \(\mathrm{t}\) years after the account opened. The account balance after 1 year is \(\$5,202.00\). Which equation could define A?

  1. \(\mathrm{A(t)} = 5,000.00(1.02)^{2\mathrm{t}}\)
  2. \(\mathrm{A(t)} = 202.00(1.02)^{2\mathrm{t}}\)
  3. \(\mathrm{A(t)} = 5,000.00(0.02)^{2\mathrm{t}}\)
  4. \(\mathrm{A(t)} = 5,000.00(1.04)^{\mathrm{t}}\)
A
\(\mathrm{A(t) = 5{,}000.00(1.02)^{2t}}\)
B
\(\mathrm{A(t) = 202.00(1.02)^{2t}}\)
C
\(\mathrm{A(t) = 5{,}000.00(0.02)^{2t}}\)
D
\(\mathrm{A(t) = 5{,}000.00(1.04)^t}\)
Solution

1. TRANSLATE the problem information

  • Given information:
    • Initial balance (P): $5,000
    • Annual interest rate: 4% = 0.04
    • Compounding: semi-annually (n = 2)
    • Balance after 1 year: $5,202
  • What this tells us: We need an exponential function that matches these conditions.

2. INFER the testing strategy

  • Since we know \(\mathrm{A(1) = 5{,}202}\), we can test each option by substituting \(\mathrm{t = 1}\)
  • The correct equation should give us exactly $5,202 when \(\mathrm{t = 1}\)
  • This is more efficient than deriving the formula from scratch

3. SIMPLIFY by testing each option

Option A: \(\mathrm{A(t) = 5{,}000(1.02)^{2t}}\)

  • \(\mathrm{A(1) = 5{,}000(1.02)^{2×1} = 5{,}000(1.02)^2}\)
  • \(\mathrm{(1.02)^2 = 1.0404}\) (use calculator)
  • \(\mathrm{5{,}000 × 1.0404 = 5{,}202}\) ✓ This matches!

Option B: \(\mathrm{A(t) = 202(1.02)^{2t}}\)

  • \(\mathrm{A(1) = 202(1.02)^2 = 202(1.0404) ≈ 210.36}\)

Option C: \(\mathrm{A(t) = 5{,}000(0.02)^{2t}}\)

  • \(\mathrm{A(1) = 5{,}000(0.02)^2 = 5{,}000(0.0004) = 2}\)

Option D: \(\mathrm{A(t) = 5{,}000(1.04)^t}\)

  • \(\mathrm{A(1) = 5{,}000(1.04)^1 = 5{,}200}\) ✗ (Close, but not exact)

Answer: A




Why Students Usually Falter on This Problem

Most Common Error Path:

Weak TRANSLATE skill: Students confuse '4% compounded semi-annually' with simple annual compounding, leading them to think the growth factor should be 1.04 per year.

They reason: '4% annual interest means multiply by 1.04 each year, so \(\mathrm{A(t) = 5{,}000(1.04)^t}\) makes sense.'

This may lead them to select Choice D (\(\mathrm{5{,}000(1.04)^t}\)) without testing, since D looks like the 'obvious' compound interest formula.


Second Most Common Error:

Inadequate SIMPLIFY execution: Students attempt to verify their choice but make calculation errors with \(\mathrm{(1.02)^2}\), getting approximately 1.04 instead of 1.0404.

This makes Option A seem to give \(\mathrm{A(1) ≈ 5{,}000(1.04) = 5{,}200}\), which doesn't match the given $5,202. They might then incorrectly eliminate the right answer and guess among the remaining choices.


The Bottom Line:

This problem tests whether students understand that semi-annual compounding splits the annual rate in half but compounds twice as often, and whether they can perform precise calculations to distinguish between very similar values ($5,200 vs $5,202).

Answer Choices Explained
A
\(\mathrm{A(t) = 5{,}000.00(1.02)^{2t}}\)
B
\(\mathrm{A(t) = 202.00(1.02)^{2t}}\)
C
\(\mathrm{A(t) = 5{,}000.00(0.02)^{2t}}\)
D
\(\mathrm{A(t) = 5{,}000.00(1.04)^t}\)
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