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For a cylinder with positive radius r and height h, the volume V is given by the formula V =...

GMAT Advanced Math : (Adv_Math) Questions

Source: Prism
Advanced Math
Nonlinear equations in 1 variable
EASY
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Notes
Post a Query

For a cylinder with positive radius \(\mathrm{r}\) and height \(\mathrm{h}\), the volume \(\mathrm{V}\) is given by the formula \(\mathrm{V = πr^2h}\). Which of the following equations correctly expresses the height \(\mathrm{h}\) in terms of \(\mathrm{V}\) and \(\mathrm{r}\)?

A
\(\mathrm{h = V - \pi r^2}\)
B
\(\mathrm{h = \frac{V}{\pi r^2}}\)
C
\(\mathrm{h = \frac{V\pi}{r^2}}\)
D
\(\mathrm{h = \frac{V}{\pi r}}\)
Solution

1. TRANSLATE the problem information

  • Given formula: \(\mathrm{V = \pi r^2h}\)
  • Goal: Express h in terms of V and r

2. INFER the algebraic strategy

  • Notice that h is being multiplied by \(\mathrm{\pi r^2}\)
  • To isolate h, I need to "undo" this multiplication by dividing both sides by \(\mathrm{\pi r^2}\)
  • This will leave h by itself on one side

3. SIMPLIFY by applying division to both sides

  • Divide both sides by \(\mathrm{\pi r^2}\):
    \(\mathrm{V \div (\pi r^2) = (\pi r^2h) \div (\pi r^2)}\)
  • On the right side, the \(\mathrm{\pi r^2}\) terms cancel:
    \(\mathrm{V/(\pi r^2) = h}\)
  • Rewrite with h on the left:
    \(\mathrm{h = V/(\pi r^2)}\)

Answer: B




Why Students Usually Falter on This Problem

Most Common Error Path:

Weak INFER skill: Students may think they should subtract \(\mathrm{\pi r^2}\) from both sides instead of dividing by it.

When students see \(\mathrm{V = \pi r^2h}\), they might think "to get h alone, I need to get rid of \(\mathrm{\pi r^2}\)" and incorrectly reason that subtracting will accomplish this. This leads to \(\mathrm{V - \pi r^2 = h}\), which would make them select Choice A (\(\mathrm{h = V - \pi r^2}\)).

Second Most Common Error:

Poor SIMPLIFY execution: Students correctly identify the need to divide by \(\mathrm{\pi r^2}\), but make errors in handling the π symbol during algebraic manipulation.

Some students might incorrectly move π to the numerator or forget that r needs to be squared in the denominator. This confusion about where π belongs could lead them to select Choice C (\(\mathrm{h = V\pi/r^2}\)) or Choice D (\(\mathrm{h = V/\pi r}\)).

The Bottom Line:

This problem tests whether students truly understand what "solving for a variable" means - you must undo operations in reverse order, and multiplication is undone by division, not subtraction.

Answer Choices Explained
A
\(\mathrm{h = V - \pi r^2}\)
B
\(\mathrm{h = \frac{V}{\pi r^2}}\)
C
\(\mathrm{h = \frac{V\pi}{r^2}}\)
D
\(\mathrm{h = \frac{V}{\pi r}}\)
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