For a cylinder with positive radius r and height h, the volume V is given by the formula V =...
GMAT Advanced Math : (Adv_Math) Questions
For a cylinder with positive radius \(\mathrm{r}\) and height \(\mathrm{h}\), the volume \(\mathrm{V}\) is given by the formula \(\mathrm{V = πr^2h}\). Which of the following equations correctly expresses the height \(\mathrm{h}\) in terms of \(\mathrm{V}\) and \(\mathrm{r}\)?
1. TRANSLATE the problem information
- Given formula: \(\mathrm{V = \pi r^2h}\)
- Goal: Express h in terms of V and r
2. INFER the algebraic strategy
- Notice that h is being multiplied by \(\mathrm{\pi r^2}\)
- To isolate h, I need to "undo" this multiplication by dividing both sides by \(\mathrm{\pi r^2}\)
- This will leave h by itself on one side
3. SIMPLIFY by applying division to both sides
- Divide both sides by \(\mathrm{\pi r^2}\):
\(\mathrm{V \div (\pi r^2) = (\pi r^2h) \div (\pi r^2)}\)
- On the right side, the \(\mathrm{\pi r^2}\) terms cancel:
\(\mathrm{V/(\pi r^2) = h}\)
- Rewrite with h on the left:
\(\mathrm{h = V/(\pi r^2)}\)
Answer: B
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak INFER skill: Students may think they should subtract \(\mathrm{\pi r^2}\) from both sides instead of dividing by it.
When students see \(\mathrm{V = \pi r^2h}\), they might think "to get h alone, I need to get rid of \(\mathrm{\pi r^2}\)" and incorrectly reason that subtracting will accomplish this. This leads to \(\mathrm{V - \pi r^2 = h}\), which would make them select Choice A (\(\mathrm{h = V - \pi r^2}\)).
Second Most Common Error:
Poor SIMPLIFY execution: Students correctly identify the need to divide by \(\mathrm{\pi r^2}\), but make errors in handling the π symbol during algebraic manipulation.
Some students might incorrectly move π to the numerator or forget that r needs to be squared in the denominator. This confusion about where π belongs could lead them to select Choice C (\(\mathrm{h = V\pi/r^2}\)) or Choice D (\(\mathrm{h = V/\pi r}\)).
The Bottom Line:
This problem tests whether students truly understand what "solving for a variable" means - you must undo operations in reverse order, and multiplication is undone by division, not subtraction.