Which of the following expressions is equivalent to \((3\mathrm{x}^2\mathrm{y} - 5\mathrm{xy} + 2) - (\mathrm{x}^2\mathrm{y} + 2\mathrm{xy} - 6)\)?
GMAT Advanced Math : (Adv_Math) Questions
Which of the following expressions is equivalent to \((3\mathrm{x}^2\mathrm{y} - 5\mathrm{xy} + 2) - (\mathrm{x}^2\mathrm{y} + 2\mathrm{xy} - 6)\)?
1. INFER the solution strategy
- When subtracting polynomials, we distribute the negative sign to every term in the second polynomial
- Then we combine like terms by adding/subtracting their coefficients
2. SIMPLIFY by distributing the negative sign
- Original: \((3\mathrm{x}^2\mathrm{y} - 5\mathrm{xy} + 2) - (\mathrm{x}^2\mathrm{y} + 2\mathrm{xy} - 6)\)
- Distribute the negative: \(3\mathrm{x}^2\mathrm{y} - 5\mathrm{xy} + 2 - \mathrm{x}^2\mathrm{y} - 2\mathrm{xy} + 6\)
- Notice that \(-(−6)\) becomes \(+6\)
3. SIMPLIFY by grouping like terms
- Group \(\mathrm{x}^2\mathrm{y}\) terms: \((3\mathrm{x}^2\mathrm{y} - \mathrm{x}^2\mathrm{y})\)
- Group \(\mathrm{xy}\) terms: \((-5\mathrm{xy} - 2\mathrm{xy})\)
- Group constants: \((2 + 6)\)
4. SIMPLIFY by combining coefficients
- \(\mathrm{x}^2\mathrm{y}\) terms: \(3 - 1 = 2\) → \(2\mathrm{x}^2\mathrm{y}\)
- \(\mathrm{xy}\) terms: \(-5 - 2 = -7\) → \(-7\mathrm{xy}\)
- Constants: \(2 + 6 = 8\)
Answer: \(2\mathrm{x}^2\mathrm{y} - 7\mathrm{xy} + 8\) (Choice B)
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak SIMPLIFY execution: Not properly distributing the negative sign to the constant term
Students correctly distribute the negative to \(\mathrm{x}^2\mathrm{y}\) and \(2\mathrm{xy}\), but forget that \(-(−6) = +6\). They keep it as \(-6\), leading to:
\(2\mathrm{x}^2\mathrm{y} - 7\mathrm{xy} + 2 - 6 = 2\mathrm{x}^2\mathrm{y} - 7\mathrm{xy} - 4\)
This leads them to select Choice A (\(2\mathrm{x}^2\mathrm{y} - 7\mathrm{xy} - 4\))
Second Most Common Error:
Weak SIMPLIFY execution: Arithmetic errors when combining the \(\mathrm{xy}\) terms
Students might incorrectly compute \(-5\mathrm{xy} - 2\mathrm{xy}\) as \(-3\mathrm{xy}\) instead of \(-7\mathrm{xy}\), possibly thinking \(-5 + 2 = -3\). This gives:
\(2\mathrm{x}^2\mathrm{y} - 3\mathrm{xy} + 8\)
This leads them to select Choice C (\(2\mathrm{x}^2\mathrm{y} - 3\mathrm{xy} + 8\))
The Bottom Line:
The key challenge is careful attention to sign changes when distributing the negative, especially with the constant term where a negative times negative becomes positive.