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(a + 5)/2 = 3b - cThe given equation relates the positive numbers a, b, and c. Which equation correctly...

GMAT Advanced Math : (Adv_Math) Questions

Source: Prism
Advanced Math
Nonlinear equations in 1 variable
EASY
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\(\frac{\mathrm{a + 5}}{2} = 3\mathrm{b} - \mathrm{c}\)

The given equation relates the positive numbers a, b, and c. Which equation correctly expresses a in terms of b and c?

  1. \(\mathrm{a} = 6\mathrm{b} - 2\mathrm{c} - 5\)
  2. \(\mathrm{a} = 6\mathrm{b} - \mathrm{c} - 5\)
  3. \(\mathrm{a} = 6\mathrm{b} - 2\mathrm{c} + 5\)
  4. \(\mathrm{a} = 3\mathrm{b} - \mathrm{c} - 5\)
A
\(\mathrm{a = 6b - 2c - 5}\)
B
\(\mathrm{a = 6b - c - 5}\)
C
\(\mathrm{a = 6b - 2c + 5}\)
D
\(\mathrm{a = 3b - c - 5}\)
Solution

1. INFER the solution strategy

  • We have: \(\frac{\mathrm{a + 5}}{2} = 3\mathrm{b} - \mathrm{c}\)
  • Goal: Express a in terms of b and c
  • Strategy: Eliminate the fraction first, then isolate a

2. SIMPLIFY by eliminating the fraction

  • Multiply both sides by 2:
    \(\frac{\mathrm{a + 5}}{2} \times 2 = (3\mathrm{b} - \mathrm{c}) \times 2\)
  • This gives us: \(\mathrm{a + 5} = 2(3\mathrm{b} - \mathrm{c})\)

3. SIMPLIFY using the distributive property

  • Distribute the 2: \(\mathrm{a + 5} = 6\mathrm{b} - 2\mathrm{c}\)
  • Now we have a linear equation without fractions

4. SIMPLIFY to isolate a

  • Subtract 5 from both sides: \(\mathrm{a} = 6\mathrm{b} - 2\mathrm{c} - 5\)

Answer: A


Why Students Usually Falter on This Problem

Most Common Error Path:

Weak SIMPLIFY execution: Students make distribution errors when expanding \(2(3\mathrm{b} - \mathrm{c})\)

Many students incorrectly distribute to get \(2(3\mathrm{b} - \mathrm{c}) = 6\mathrm{b} - \mathrm{c}\) (forgetting to multiply the -c by 2), leading to:
\(\mathrm{a + 5} = 6\mathrm{b} - \mathrm{c}\)
\(\mathrm{a} = 6\mathrm{b} - \mathrm{c} - 5\)

This may lead them to select Choice B (\(\mathrm{a} = 6\mathrm{b} - \mathrm{c} - 5\))

Second Most Common Error:

Poor SIMPLIFY execution: Sign errors when moving the constant term

Students correctly get to \(\mathrm{a + 5} = 6\mathrm{b} - 2\mathrm{c}\), but then make a sign error when subtracting 5, thinking:
\(\mathrm{a} = 6\mathrm{b} - 2\mathrm{c} + 5\)

This may lead them to select Choice C (\(\mathrm{a} = 6\mathrm{b} - 2\mathrm{c} + 5\))

The Bottom Line:

This problem tests careful algebraic manipulation. The key is systematic execution: multiply first to clear fractions, then distribute carefully, and finally isolate the variable while tracking all signs correctly.

Answer Choices Explained
A
\(\mathrm{a = 6b - 2c - 5}\)
B
\(\mathrm{a = 6b - c - 5}\)
C
\(\mathrm{a = 6b - 2c + 5}\)
D
\(\mathrm{a = 3b - c - 5}\)
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