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At a conference, there are a total of 275 attendees. Each attendee is assigned to either group A, group B,...

GMAT Problem-Solving and Data Analysis : (PS_DA) Questions

Source: Official
Problem-Solving and Data Analysis
Probability and conditional probability
MEDIUM
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Notes
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At a conference, there are a total of 275 attendees. Each attendee is assigned to either group A, group B, or group C. If one of these attendees is selected at random, the probability of selecting an attendee who is assigned to group A is 0.44 and the probability of selecting an attendee who is assigned to group B is 0.24. How many attendees are assigned to group C?

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Solution

1. TRANSLATE the problem information

  • Given information:
    • Total attendees: 275 people
    • Probability of selecting Group A member: 0.44
    • Probability of selecting Group B member: 0.24
    • Each person is assigned to exactly one group (A, B, or C)
  • What we need to find: Number of people in Group C

2. INFER the key relationship

  • Since every attendee is assigned to exactly one group, the probabilities of selecting from each group must add up to 1
  • This means: \(\mathrm{P(Group\,A) + P(Group\,B) + P(Group\,C) = 1}\)
  • We can use this to find \(\mathrm{P(Group\,C)}\)

3. SIMPLIFY to find P(Group C)

  • \(\mathrm{P(Group\,C) = 1 - P(Group\,A) - P(Group\,B)}\)
  • \(\mathrm{P(Group\,C) = 1 - 0.44 - 0.24 = 0.32}\)

4. TRANSLATE probability to actual count

  • If \(\mathrm{P(Group\,C) = 0.32}\), then 32% of all attendees are in Group C
  • Number in Group C = \(\mathrm{0.32 \times 275 = 88}\) people

Answer: 88




Why Students Usually Falter on This Problem

Most Common Error Path:

Weak INFER reasoning: Students don't recognize that the probabilities must sum to 1. Instead, they might try to work with the given probabilities directly without finding \(\mathrm{P(Group\,C)}\) first.

For example, they might incorrectly calculate: \(\mathrm{275 \times 0.44 = 121}\), then \(\mathrm{275 \times 0.24 = 66}\), then think the answer is \(\mathrm{121 + 66 = 187}\). This shows they're confusing what the question is asking and not using the complement relationship.

This leads to confusion and incorrect calculations.

Second Most Common Error:

Incomplete SIMPLIFY execution: Students correctly identify that \(\mathrm{P(Group\,C) = 1 - 0.44 - 0.24}\), but make arithmetic errors in the subtraction or the final multiplication.

Common calculation mistakes include:

  • Getting \(\mathrm{P(Group\,C) = 0.22}\) instead of 0.32
  • Multiplying incorrectly: \(\mathrm{0.32 \times 275 \neq 88}\)

This may lead them to select an incorrect numerical answer.

The Bottom Line:

This problem tests whether students understand that probabilities in a complete system must sum to 1. The key insight is recognizing the complement relationship rather than trying to work with incomplete information.

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