\((\mathrm{ax} - 1)(3\mathrm{x}^2 + \mathrm{bx} - 5) = 12\mathrm{x}^3 - \mathrm{cx}^2 - 23\mathrm{x} + 5\) The equation above is true...
GMAT Advanced Math : (Adv_Math) Questions
\((\mathrm{ax} - 1)(3\mathrm{x}^2 + \mathrm{bx} - 5) = 12\mathrm{x}^3 - \mathrm{cx}^2 - 23\mathrm{x} + 5\)
The equation above is true for all x, where a, b, and c are constants. What is the value of c?
-9
9
12
18
1. INFER the solution strategy
Since the equation is true for all x, the polynomials on both sides must be identical. This means I need to expand the left side and match coefficients.
2. SIMPLIFY by expanding the left side
- Expand \((\mathrm{ax} - 1)(3\mathrm{x}^2 + \mathrm{bx} - 5)\):
- First: \(\mathrm{ax}(3\mathrm{x}^2 + \mathrm{bx} - 5) = 3\mathrm{ax}^3 + \mathrm{abx}^2 - 5\mathrm{ax}\)
- Second: \(-1(3\mathrm{x}^2 + \mathrm{bx} - 5) = -3\mathrm{x}^2 - \mathrm{bx} + 5\)
- Combined: \(3\mathrm{ax}^3 + \mathrm{abx}^2 - 5\mathrm{ax} - 3\mathrm{x}^2 - \mathrm{bx} + 5\)
3. SIMPLIFY by collecting like terms
- Group by powers of x:
- \(\mathrm{x}^3\) terms: \(3\mathrm{ax}^3\)
- \(\mathrm{x}^2\) terms: \(\mathrm{abx}^2 - 3\mathrm{x}^2 = (\mathrm{ab} - 3)\mathrm{x}^2\)
- \(\mathrm{x}^1\) terms: \(-5\mathrm{ax} - \mathrm{bx} = (-5\mathrm{a} - \mathrm{b})\mathrm{x}\)
- Constant: \(5\)
- Result: \(3\mathrm{ax}^3 + (\mathrm{ab} - 3)\mathrm{x}^2 + (-5\mathrm{a} - \mathrm{b})\mathrm{x} + 5\)
4. INFER the coefficient equations
Setting equal to \(12\mathrm{x}^3 - \mathrm{cx}^2 - 23\mathrm{x} + 5\):
- Coefficient of \(\mathrm{x}^3\): \(3\mathrm{a} = 12\)
- Coefficient of \(\mathrm{x}^2\): \(\mathrm{ab} - 3 = -\mathrm{c}\)
- Coefficient of \(\mathrm{x}^1\): \(-5\mathrm{a} - \mathrm{b} = -23\)
- Constant term: \(5 = 5\) ✓
5. SIMPLIFY by solving the system
- From \(\mathrm{x}^3\) equation: \(3\mathrm{a} = 12\)
\(\mathrm{a} = 4\)
- From \(\mathrm{x}^1\) equation: \(-5\mathrm{a} - \mathrm{b} = -23\)
\(-5(4) - \mathrm{b} = -23\)
\(-20 - \mathrm{b} = -23\)
\(\mathrm{b} = 3\)
- From \(\mathrm{x}^2\) equation: \(\mathrm{ab} - 3 = -\mathrm{c}\)
\((4)(3) - 3 = -\mathrm{c}\)
\(12 - 3 = -\mathrm{c}\)
\(9 = -\mathrm{c}\)
\(\mathrm{c} = -9\)
Answer: A. -9
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak SIMPLIFY execution: Students correctly set up \(\mathrm{ab} - 3 = -\mathrm{c}\) but forget the negative sign when solving for c.
They calculate \(\mathrm{ab} - 3 = (4)(3) - 3 = 9\), then incorrectly conclude \(\mathrm{c} = 9\) instead of \(\mathrm{c} = -9\). The equation \(\mathrm{ab} - 3 = -\mathrm{c}\) means c is the negative of \((\mathrm{ab} - 3)\).
This leads them to select Choice B (9).
Second Most Common Error:
Poor INFER reasoning: Students get confused about which coefficient corresponds to which term, especially when dealing with the \(-\mathrm{cx}^2\) term.
They might incorrectly associate c with a different coefficient (like the \(\mathrm{x}^3\) coefficient of 12) rather than systematically matching each term.
This causes them to get stuck and guess among the remaining choices.
The Bottom Line:
This problem tests whether students can systematically handle polynomial identities and carefully track signs through multi-step algebraic manipulation. The key insight is recognizing that \(\mathrm{ab} - 3 = -\mathrm{c}\) means \(\mathrm{c} = -(\mathrm{ab} - 3)\), not \(\mathrm{c} = \mathrm{ab} - 3\).
-9
9
12
18