Bacteria are growing in a liquid growth medium. There were 300{,000} cells per milliliter during an initial observation. The number...
GMAT Advanced Math : (Adv_Math) Questions
Bacteria are growing in a liquid growth medium. There were \(\mathrm{300{,}000}\) cells per milliliter during an initial observation. The number of cells per milliliter doubles every \(\mathrm{3}\) hours. How many cells per milliliter will there be \(\mathrm{15}\) hours after the initial observation?
1,500,000
2,400,000
4,500,000
9,600,000
1. TRANSLATE the problem information
- Given information:
- Initial amount: 300,000 cells per milliliter
- Growth pattern: doubles every 3 hours
- Time elapsed: 15 hours
- Find: number of cells after 15 hours
- What this tells us: This is exponential growth since the population multiplies by a constant factor over equal time periods.
2. INFER the mathematical approach
- Since the bacteria population doubles at regular intervals, this requires an exponential growth formula
- The general form is: \(\mathrm{y = a(b)^{(t/k)}}\) where:
- \(\mathrm{a}\) = initial amount
- \(\mathrm{b}\) = growth factor per time period
- \(\mathrm{k}\) = length of each time period
- \(\mathrm{t}\) = total elapsed time
3. TRANSLATE each piece into the formula
- \(\mathrm{a = 300,000}\) (initial observation)
- \(\mathrm{b = 2}\) (since "doubles" means multiplies by 2)
- \(\mathrm{k = 3}\) (doubles every 3 hours)
- \(\mathrm{t = 15}\) (we want the amount after 15 hours)
- Formula becomes: \(\mathrm{y = 300,000(2)^{(15/3)}}\)
4. SIMPLIFY the exponent and calculate
- First: \(\mathrm{15/3 = 5}\), so \(\mathrm{y = 300,000(2)^5}\)
- Calculate \(\mathrm{2^5 = 2 × 2 × 2 × 2 × 2 = 32}\)
- Final calculation: \(\mathrm{y = 300,000 × 32 = 9,600,000}\) (use calculator)
Answer: D. 9,600,000
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak INFER skill: Students misinterpret this as linear growth instead of exponential growth.
They might think: "If it doubles every 3 hours, then in 15 hours (which is 5 periods of 3 hours), it increases by \(\mathrm{5 × 300,000 = 1,500,000}\), giving a total of \(\mathrm{300,000 + 1,500,000 = 1,800,000}\)." This type of additive thinking ignores that each doubling applies to the current population, not the original.
This may lead them to select Choice A (1,500,000) or get confused and guess.
Second Most Common Error:
Poor TRANSLATE reasoning: Students correctly recognize exponential growth but use 15 directly as the exponent instead of 15/3.
They set up: \(\mathrm{y = 300,000(2)^{15}}\), which gives an astronomically large number that doesn't match any answer choice. This causes them to get stuck and randomly select an answer.
The Bottom Line:
The key challenge is recognizing that "doubles every 3 hours" creates exponential, not linear, growth. Each doubling multiplies the current population by 2, creating the compounding effect that makes exponential growth so powerful.
1,500,000
2,400,000
4,500,000
9,600,000