A biologist is studying a culture of bacteria. The initial population of the culture was 2,000 bacteria. Due to the...
GMAT Advanced Math : (Adv_Math) Questions
A biologist is studying a culture of bacteria. The initial population of the culture was 2,000 bacteria. Due to the application of a new disinfectant, the population is reduced by 25% every 4 hours. Which of the following functions, \(\mathrm{B(t)}\), models the population of bacteria \(\mathrm{t}\) hours after the disinfectant is applied?
\(\mathrm{B(t) = 2000(0.25)^{4t}}\)
\(\mathrm{B(t) = 2000(0.75)^{t/4}}\)
\(\mathrm{B(t) = 2000(0.75)^{4t}}\)
\(\mathrm{B(t) = 2000(1.25)^{t/4}}\)
1. TRANSLATE the problem information
- Given information:
- Initial population: 2,000 bacteria
- Population reduces by 25% every 4 hours
- Need to find \(\mathrm{B(t)}\) = population after \(\mathrm{t}\) hours
- What this tells us: We have an exponential decay situation with a specific time period
2. INFER the exponential decay model structure
- For exponential decay problems, we use: \(\mathrm{F(t) = P \times b^{(t/k)}}\)
- \(\mathrm{P}\) = initial amount
- \(\mathrm{b}\) = decay factor (fraction that remains after each period)
- \(\mathrm{t/k}\) = number of decay periods that occur in time \(\mathrm{t}\)
3. TRANSLATE each component from the problem
- Initial amount: \(\mathrm{P = 2000}\)
- Decay factor: If 25% is removed, then \(\mathrm{100\% - 25\% = 75\%}\) remains
So \(\mathrm{b = 0.75}\) - Time period: \(\mathrm{k = 4}\) hours (decay happens every 4 hours)
4. INFER the correct exponent
- Since decay happens every 4 hours, in \(\mathrm{t}\) hours there are \(\mathrm{t/4}\) periods
- So the exponent should be \(\mathrm{t/4}\)
5. Assemble the final function
- \(\mathrm{B(t) = P \times b^{(t/k)}}\)
- \(\mathrm{B(t) = 2000 \times (0.75)^{(t/4)}}\)
Answer: B. \(\mathrm{B(t) = 2000(0.75)^{(t/4)}}\)
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak TRANSLATE skill: Students confuse the decay factor by using 0.25 instead of 0.75
Students see "reduced by 25%" and directly use 0.25 as the decay factor, not realizing this represents what's lost, not what remains. They think: "25% reduction means multiply by 0.25 each period."
This may lead them to select Choice A (\(\mathrm{B(t) = 2000(0.25)^{4t}}\)) - though this also has the wrong exponent structure.
Second Most Common Error:
Poor INFER reasoning about the exponent: Students incorrectly construct the time relationship
Students might think: "Every 4 hours means multiply the time by 4" instead of recognizing that \(\mathrm{t/4}\) represents how many 4-hour periods fit into \(\mathrm{t}\) hours. They reverse the relationship.
This may lead them to select Choice C (\(\mathrm{B(t) = 2000(0.75)^{4t}}\)) - correct decay factor but wrong time structure.
The Bottom Line:
The key challenge is distinguishing between what's lost (25%) versus what remains (75%), combined with correctly modeling how time periods work in exponential functions.
\(\mathrm{B(t) = 2000(0.25)^{4t}}\)
\(\mathrm{B(t) = 2000(0.75)^{t/4}}\)
\(\mathrm{B(t) = 2000(0.75)^{4t}}\)
\(\mathrm{B(t) = 2000(1.25)^{t/4}}\)