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A biologist is studying a culture of bacteria. The initial population of the culture was 2,000 bacteria. Due to the...

GMAT Advanced Math : (Adv_Math) Questions

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Advanced Math
Nonlinear functions
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A biologist is studying a culture of bacteria. The initial population of the culture was 2,000 bacteria. Due to the application of a new disinfectant, the population is reduced by 25% every 4 hours. Which of the following functions, \(\mathrm{B(t)}\), models the population of bacteria \(\mathrm{t}\) hours after the disinfectant is applied?

A

\(\mathrm{B(t) = 2000(0.25)^{4t}}\)

B

\(\mathrm{B(t) = 2000(0.75)^{t/4}}\)

C

\(\mathrm{B(t) = 2000(0.75)^{4t}}\)

D

\(\mathrm{B(t) = 2000(1.25)^{t/4}}\)

Solution

1. TRANSLATE the problem information

  • Given information:
    • Initial population: 2,000 bacteria
    • Population reduces by 25% every 4 hours
    • Need to find \(\mathrm{B(t)}\) = population after \(\mathrm{t}\) hours
  • What this tells us: We have an exponential decay situation with a specific time period

2. INFER the exponential decay model structure

  • For exponential decay problems, we use: \(\mathrm{F(t) = P \times b^{(t/k)}}\)
  • \(\mathrm{P}\) = initial amount
  • \(\mathrm{b}\) = decay factor (fraction that remains after each period)
  • \(\mathrm{t/k}\) = number of decay periods that occur in time \(\mathrm{t}\)

3. TRANSLATE each component from the problem

  • Initial amount: \(\mathrm{P = 2000}\)
  • Decay factor: If 25% is removed, then \(\mathrm{100\% - 25\% = 75\%}\) remains
    So \(\mathrm{b = 0.75}\)
  • Time period: \(\mathrm{k = 4}\) hours (decay happens every 4 hours)

4. INFER the correct exponent

  • Since decay happens every 4 hours, in \(\mathrm{t}\) hours there are \(\mathrm{t/4}\) periods
  • So the exponent should be \(\mathrm{t/4}\)

5. Assemble the final function

  • \(\mathrm{B(t) = P \times b^{(t/k)}}\)
  • \(\mathrm{B(t) = 2000 \times (0.75)^{(t/4)}}\)

Answer: B. \(\mathrm{B(t) = 2000(0.75)^{(t/4)}}\)





Why Students Usually Falter on This Problem

Most Common Error Path:

Weak TRANSLATE skill: Students confuse the decay factor by using 0.25 instead of 0.75

Students see "reduced by 25%" and directly use 0.25 as the decay factor, not realizing this represents what's lost, not what remains. They think: "25% reduction means multiply by 0.25 each period."

This may lead them to select Choice A (\(\mathrm{B(t) = 2000(0.25)^{4t}}\)) - though this also has the wrong exponent structure.

Second Most Common Error:

Poor INFER reasoning about the exponent: Students incorrectly construct the time relationship

Students might think: "Every 4 hours means multiply the time by 4" instead of recognizing that \(\mathrm{t/4}\) represents how many 4-hour periods fit into \(\mathrm{t}\) hours. They reverse the relationship.

This may lead them to select Choice C (\(\mathrm{B(t) = 2000(0.75)^{4t}}\)) - correct decay factor but wrong time structure.

The Bottom Line:

The key challenge is distinguishing between what's lost (25%) versus what remains (75%), combined with correctly modeling how time periods work in exponential functions.

Answer Choices Explained
A

\(\mathrm{B(t) = 2000(0.25)^{4t}}\)

B

\(\mathrm{B(t) = 2000(0.75)^{t/4}}\)

C

\(\mathrm{B(t) = 2000(0.75)^{4t}}\)

D

\(\mathrm{B(t) = 2000(1.25)^{t/4}}\)

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