On day 0, a bacterial culture contained 400 bacteria. Every 6 hours after day 0, the bacteria population decreases to...
GMAT Advanced Math : (Adv_Math) Questions
On day 0, a bacterial culture contained 400 bacteria. Every 6 hours after day 0, the bacteria population decreases to 80% of what it was 6 hours earlier. The function \(\mathrm{h}\) gives the number of bacteria \(\mathrm{t}\) hours after day 0. Which equation defines \(\mathrm{h}\)?
1. TRANSLATE the problem information
- Given information:
- Day 0: 400 bacteria
- Every 6 hours: population decreases to 80% of what it was
- What this tells us: We multiply by \(0.8\) every 6-hour period
2. INFER the mathematical pattern
- Since "decreases to 80%" means the new amount is 80% of the old amount, we multiply by \(0.8\)
- This multiplication happens every 6 hours
- We need to figure out how many 6-hour periods occur in t hours
3. INFER the exponent structure
- After 6 hours: \(400(0.8)^1\)
- After 12 hours: \(400(0.8)^2\)
- After 18 hours: \(400(0.8)^3\)
- After t hours: We've had t/6 periods of 6 hours, so \(400(0.8)^{\mathrm{t/6}}\)
4. Match to answer choices
- Looking for: initial value 400, base 0.8, exponent t/6
- Choice D: \(\mathrm{h(t)} = 400(0.8)^{\mathrm{t/6}}\) ✓
Answer: D
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak INFER skill: Confusing "decreases to 80%" with "decreases by 80%"
Students think: "If it decreases by 80%, then only 20% remains, so I multiply by 0.2"
This leads them to look for 0.2 as the base and select Choice A (\(400(0.2)^{\mathrm{t/6}}\)) or Choice B (\(400(0.2)^{6\mathrm{t}}\))
Second Most Common Error:
Poor INFER reasoning about time intervals: Getting the exponent backwards
Students think: "Every 6 hours something happens, so after t hours, it should be something with 6t"
This may lead them to select Choice C (\(400(0.8)^{6\mathrm{t}}\))
The Bottom Line:
This problem requires careful attention to language ("to 80%" vs "by 80%") and understanding how time intervals translate to exponents in exponential functions.