Question:A ball is launched upward from a platform, and its height \(\mathrm{h(t)}\), in meters, t seconds after launch is modeled...
GMAT Advanced Math : (Adv_Math) Questions
A ball is launched upward from a platform, and its height \(\mathrm{h(t)}\), in meters, \(\mathrm{t}\) seconds after launch is modeled by \(\mathrm{h(t) = -4.9t^2 + 19.6t + 3}\). According to the model, at what time \(\mathrm{t}\) does the ball reach its maximum height? Express your answer as a fraction in lowest terms.
1. TRANSLATE the problem information
- Given information:
- Height function: \(\mathrm{h(t) = -4.9t^2 + 19.6t + 3}\)
- Need to find: time when ball reaches maximum height
- This is asking for when a quadratic function reaches its maximum value
2. INFER the mathematical approach
- Since the coefficient of \(\mathrm{t^2}\) is negative (-4.9), this parabola opens downward
- A downward-opening parabola has its maximum at the vertex
- For any quadratic \(\mathrm{f(t) = at^2 + bt + c}\), the vertex occurs at \(\mathrm{t = -b/(2a)}\)
3. SIMPLIFY using the vertex formula
- Identify the coefficients: \(\mathrm{a = -4.9, b = 19.6, c = 3}\)
- Apply the vertex formula: \(\mathrm{t = -b/(2a)}\)
- Substitute: \(\mathrm{t = -19.6/(2(-4.9))}\) \(\mathrm{= -19.6/(-9.8)}\) \(\mathrm{= 19.6/9.8}\) \(\mathrm{= 2}\)
Answer: 2
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak TRANSLATE skill: Not recognizing this as a vertex-finding problem for a quadratic function.
Students may see the quadratic equation but not immediately connect that 'maximum height' means finding the vertex. They might try to set \(\mathrm{h(t) = 0}\) to find when the ball hits the ground, or attempt other approaches that don't directly address the maximum.
This leads to confusion and guessing.
Second Most Common Error:
Poor SIMPLIFY execution: Making arithmetic errors when applying the vertex formula.
Students correctly identify the need to use \(\mathrm{t = -b/(2a)}\) but make computational mistakes. Common errors include:
- Wrong signs: \(\mathrm{t = -19.6/(2(4.9))}\) instead of \(\mathrm{t = -19.6/(2(-4.9))}\)
- Arithmetic mistakes: Getting \(\mathrm{19.6/9.8 \neq 2}\)
- Not simplifying the fraction properly
This may lead them to select incorrect numerical answers if given multiple choice options.
The Bottom Line:
This problem tests whether students can connect the physical concept of 'maximum height' with the mathematical concept of finding a parabola's vertex, then execute the vertex formula correctly.