The boiling point of water at sea level is 212 degrees Fahrenheit (°F). For every 550 feet above sea level,...
GMAT Algebra : (Alg) Questions
The boiling point of water at sea level is \(212\) degrees Fahrenheit (°F). For every \(550\) feet above sea level, the boiling point of water is lowered by about \(1\)°F. Which of the following equations can be used to find the boiling point \(\mathrm{B}\) of water, in °F, \(\mathrm{x}\) feet above sea level?
\(\mathrm{B = 550 + \frac{x}{212}}\)
\(\mathrm{B = 550 - \frac{x}{212}}\)
\(\mathrm{B = 212 + \frac{x}{550}}\)
\(\mathrm{B = 212 - \frac{x}{550}}\)
1. TRANSLATE the given information
- Given information:
- Base condition: Boiling point at sea level = \(212°\mathrm{F}\)
- Rate of change: Every \(550\) feet up → temperature drops \(1°\mathrm{F}\)
- Variable: \(\mathrm{x}\) feet above sea level
- Find: Equation for boiling point B
- What this tells us: We have a starting value (\(212°\mathrm{F}\)) that decreases at a constant rate as altitude increases.
2. INFER how the rate applies to any height
- At \(\mathrm{x}\) feet above sea level, we need to calculate how many 550-foot increments that represents
- Number of increments = \(\mathrm{x} ÷ 550 = \frac{\mathrm{x}}{550}\)
- Each increment reduces temperature by \(1°\mathrm{F}\)
- Total temperature reduction = \(\frac{\mathrm{x}}{550} × 1°\mathrm{F} = \frac{\mathrm{x}}{550}\) degrees
3. TRANSLATE "lowered by" into mathematical operation
- "Lowered by" means we subtract the reduction from the base temperature
- Boiling point = Base temperature - Total reduction
- \(\mathrm{B} = 212 - \frac{\mathrm{x}}{550}\)
Answer: D. \(\mathrm{B} = 212 - \frac{\mathrm{x}}{550}\)
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak TRANSLATE skill: Students misinterpret "lowered by" and think temperature increases with altitude instead of decreases.
They reason: "Higher altitude means higher temperature" and create the equation \(\mathrm{B} = 212 + \frac{\mathrm{x}}{550}\). This leads them to select Choice C (\(\mathrm{B} = 212 + \frac{\mathrm{x}}{550}\)).
Second Most Common Error:
Poor TRANSLATE reasoning: Students confuse which number represents the base temperature versus the rate increment.
They mix up \(212°\mathrm{F}\) (the base temperature) and \(550\) feet (the rate increment), thinking \(550°\mathrm{F}\) is the starting temperature. This confusion leads them to select Choice A (\(\mathrm{B} = 550 + \frac{\mathrm{x}}{212}\)) or Choice B (\(\mathrm{B} = 550 - \frac{\mathrm{x}}{212}\)).
The Bottom Line:
This problem tests your ability to translate a real-world rate relationship into mathematical form. The key insight is recognizing that "every 550 feet" creates the fraction \(\frac{\mathrm{x}}{550}\), and "lowered by" means subtraction from the base value of \(212°\mathrm{F}\).
\(\mathrm{B = 550 + \frac{x}{212}}\)
\(\mathrm{B = 550 - \frac{x}{212}}\)
\(\mathrm{B = 212 + \frac{x}{550}}\)
\(\mathrm{B = 212 - \frac{x}{550}}\)