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The box plot above shows the distribution of lengths, in millimeters, of 50 manufactured parts measured during quality control. Due...

GMAT Problem-Solving and Data Analysis : (PS_DA) Questions

Source: Prism
Problem-Solving and Data Analysis
One-variable data: distributions and measures of center and spread
HARD
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The box plot above shows the distribution of lengths, in millimeters, of 50 manufactured parts measured during quality control. Due to a calibration error, each measurement was \(\mathrm{3\,mm}\) less than the actual length. What is the interquartile range (IQR) of the actual lengths?

A

3

B

6

C

9

D

12

Solution

1. TRANSLATE the box plot information

Looking at the box plot carefully:

  • Q1 (first quartile): The left edge of the gray box = 22 mm
  • Q3 (third quartile): The right edge of the gray box = 28 mm
  • Median: The vertical line inside the box ≈ 25 mm

The problem tells us: "each measurement was 3 mm less than the actual length"

This means: Actual length = Measured length + 3


2. SIMPLIFY to find the measured IQR

Using the IQR formula:

  • IQR (measured) = Q3 - Q1
  • IQR (measured) = 28 - 22 = 6 mm

3. INFER the key insight about transformations

Here's the critical question: When we add 3 mm to every measurement, what happens to the IQR?

Let's find the actual quartiles:

  • Q1_actual = 22 + 3 = 25 mm
  • Q3_actual = 28 + 3 = 31 mm

Now calculate the actual IQR:

  • IQR (actual) = Q3_actual - Q1_actual
  • IQR (actual) = 31 - 25 = 6 mm

Key insight: Both quartiles shifted up by 3 mm, so their difference stayed the same!

Mathematical principle: When you add (or subtract) the same constant to every value in a dataset, the spread doesn't change—only the center shifts. The IQR measures spread, so it remains unchanged.

Answer: B (6 mm)




Why Students Usually Falter on This Problem

Most Common Error Path:

Weak INFER skill: Students incorrectly think that since each individual measurement needs to be adjusted by 3 mm, the IQR should also be adjusted by 3 mm.

This faulty reasoning goes: "The measurements are off by 3 mm, so I need to add 3 to the IQR: 6 + 3 = 9 mm."

This error comes from not understanding what IQR represents. IQR is a measure of spread (the distance between Q3 and Q1), not a measure of center (like the mean or median). When you add a constant to all values:

  • Measures of center shift by that constant (mean and median both increase by 3)
  • Measures of spread stay the same (IQR, range, and standard deviation don't change)

This may lead them to select Choice C (9).

Second Most Common Error:

Poor TRANSLATE reasoning: Students misread the box plot and incorrectly identify the quartiles, perhaps confusing the median line with Q1 or Q3, or misreading the scale.

For example, if they think Q1 = 20 and Q3 = 28, they'd calculate IQR = 8 mm. Then they might either:

  • Keep 8 mm as their answer (not matching any choice, leading to confusion)
  • Add 3 to get 11 mm (also not matching, causing guessing)

This confusion about reading the box plot correctly causes them to get stuck and guess among the choices.

The Bottom Line:

This problem tests two things simultaneously: (1) your ability to read a box plot accurately, and (2) your understanding of how transformations affect measures of spread versus measures of center. The "adjustment by 3 mm" is designed to trap students who don't recognize that IQR measures spread, which is invariant under constant shifts.

Answer Choices Explained
A

3

B

6

C

9

D

12

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