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A company uses the formula C = nh + F to calculate the total cost, C, in dollars, to produce...

GMAT Advanced Math : (Adv_Math) Questions

Source: Prism
Advanced Math
Nonlinear equations in 1 variable
EASY
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Notes
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A company uses the formula \(\mathrm{C = nh + F}\) to calculate the total cost, \(\mathrm{C}\), in dollars, to produce a batch of a certain product. In the formula, \(\mathrm{n}\) is the number of units in the batch, \(\mathrm{h}\) is the cost for labor per unit in dollars, and \(\mathrm{F}\) is a fixed setup fee in dollars. Which of the following correctly expresses the number of units, \(\mathrm{n}\), in terms of \(\mathrm{C}\), \(\mathrm{h}\), and \(\mathrm{F}\)?

A
\(\mathrm{n = \frac{C - F}{h}}\)
B
\(\mathrm{n = \frac{C + F}{h}}\)
C
\(\mathrm{n = \frac{C}{h} - F}\)
D
\(\mathrm{n = C - F - h}\)
Solution

1. TRANSLATE the problem information

  • Given: The cost formula \(\mathrm{C = nh + F}\) where C is total cost, n is number of units, h is cost per unit, and F is fixed setup fee
  • Find: Express n in terms of the other variables

2. INFER the solution strategy

  • This is a 'solve for the variable' problem
  • I need to isolate n on one side of the equation using inverse operations
  • Since n is currently multiplied by h and then has F added to it, I need to undo these operations in reverse order

3. SIMPLIFY by removing the constant term first

  • Start with: \(\mathrm{C = nh + F}\)
  • Subtract F from both sides: \(\mathrm{C - F = nh}\)
  • This eliminates F from the right side

4. SIMPLIFY by isolating the variable

  • Now I have: \(\mathrm{C - F = nh}\)
  • Divide both sides by h: \(\mathrm{\frac{C - F}{h} = n}\)
  • This gives me: \(\mathrm{n = \frac{C - F}{h}}\)

Answer: A




Why Students Usually Falter on This Problem

Most Common Error Path:

Weak INFER skill: Students don't recognize the proper order of operations for isolating variables. They might try to divide by h first, leading to something like \(\mathrm{\frac{C}{h} = n + \frac{F}{h}}\), then incorrectly attempt to subtract F instead of \(\mathrm{\frac{F}{h}}\).

This type of confusion about operation order can lead them to select Choice C \(\mathrm{(\frac{C}{h} - F)}\) or cause them to get stuck and guess.


Second Most Common Error:

Poor SIMPLIFY execution: Students make sign errors when moving terms across the equals sign. They might incorrectly add F instead of subtracting it when trying to isolate the nh term.

This leads them to write \(\mathrm{C + F = nh}\), and then \(\mathrm{n = \frac{C + F}{h}}\), causing them to select Choice B \(\mathrm{(\frac{C + F}{h})}\).


The Bottom Line:

Success on this problem requires systematic thinking about inverse operations and careful algebraic manipulation. Students who rush or don't have a clear strategy for variable isolation are most likely to make errors.

Answer Choices Explained
A
\(\mathrm{n = \frac{C - F}{h}}\)
B
\(\mathrm{n = \frac{C + F}{h}}\)
C
\(\mathrm{n = \frac{C}{h} - F}\)
D
\(\mathrm{n = C - F - h}\)
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