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The graph shown models the number of candy bars a certain machine wraps with a label in x seconds. According...

GMAT Algebra : (Alg) Questions

Source: Practice Test
Algebra
Linear functions
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The graph shown models the number of candy bars a certain machine wraps with a label in x seconds. According to the graph, what is the estimated number of candy bars the machine wraps with a label per second?

A

\(\mathrm{2}\)

B

\(\mathrm{40}\)

C

\(\mathrm{78}\)

D

\(\mathrm{80}\)

Solution

1. TRANSLATE the question

  • The question asks: "what is the estimated number of candy bars the machine wraps with a label per second?"
  • Key phrase: "per second" - this means rate (how many candy bars for each second of time)

2. INFER what mathematical concept matches this question

  • When we see "per second" in a graph where:
    • x-axis = time (seconds)
    • y-axis = quantity (candy bars)
  • We need to find: How much does y change when x increases by 1?
  • This is the slope of the line!
  • The slope tells us the rate of change - exactly what "per second" is asking for

3. TRANSLATE coordinates from the graph

Looking at the graph, identify two clear points the line passes through:

  • Point 1: \(\mathrm{(0, 0)}\) - at 0 seconds, 0 candy bars
  • Point 2: \(\mathrm{(2, 80)}\) - at 2 seconds, 80 candy bars

You could also use \(\mathrm{(4, 160)}\) or other visible points, but \(\mathrm{(0, 0)}\) and \(\mathrm{(2, 80)}\) are easiest to read.


4. Apply the slope formula and SIMPLIFY

  • Slope formula: \(\mathrm{m = \frac{y_2 - y_1}{x_2 - x_1}}\)
  • Substitute the points:
    \(\mathrm{m = \frac{80 - 0}{2 - 0}}\)
    \(\mathrm{m = \frac{80}{2}}\)
    \(\mathrm{m = 40}\)
  • This means 40 candy bars are wrapped per second

Answer: B. 40




Why Students Usually Falter on This Problem


Most Common Error Path:

Weak INFER skill: Not connecting "per second" to the concept of slope

Students might think "per second" means they should look at what happens at \(\mathrm{x = 1}\) second or \(\mathrm{x = 2}\) seconds. Looking at the graph, at \(\mathrm{x = 2}\), the y-value is 80. A student might think this is the answer because they read the coordinates but didn't understand that "per second" requires calculating the rate (slope), not just reading a single y-value.

This may lead them to select Choice D (80).


Second Most Common Error:

Incomplete SIMPLIFY execution: Reading coordinates incorrectly or using the wrong points

If a student misreads the graph and thinks the line passes through \(\mathrm{(2, 78)}\) instead of \(\mathrm{(2, 80)}\), they would calculate:

  • \(\mathrm{m = \frac{78 - 0}{2 - 0} = \frac{78}{2} = 39}\)

Since 78 is an answer choice and close to their calculation, this may lead them to select Choice C (78).


Third Error Path:

TRANSLATE confusion: Mixing up which variable represents rate

A very confused student might think the answer is how many seconds per candy bar rather than candy bars per second, leading to calculations like \(\mathrm{\frac{2}{80}}\) or similar backwards reasoning. However, since none of the decimals appear in the choices, this would cause confusion and guessing.


The Bottom Line:

The key challenge is recognizing that "per second" on a graph means finding the slope (rate of change). Students who treat this as a simple reading-the-graph problem rather than a rate-calculation problem will select wrong answers that represent y-values at specific points rather than the slope of the line.

Answer Choices Explained
A

\(\mathrm{2}\)

B

\(\mathrm{40}\)

C

\(\mathrm{78}\)

D

\(\mathrm{80}\)

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