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What is the center of the circle in the xy-plane defined by the equation \((\mathrm{x} - 1)^2 + (\mathrm{y} +...

GMAT Geometry & Trigonometry : (Geo_Trig) Questions

Source: Official
Geometry & Trigonometry
Circles
MEDIUM
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Notes
Post a Query

What is the center of the circle in the xy-plane defined by the equation \((\mathrm{x} - 1)^2 + (\mathrm{y} + 7)^2 = 1\)?

A
\((-1, -7)\)
B
\((-1, 7)\)
C
\((1, -7)\)
D
\((1, 7)\)
Solution

1. TRANSLATE the given equation to standard form pattern

  • Given equation: \((x - 1)^2 + (y + 7)^2 = 1\)
  • Standard form: \((x - h)^2 + (y - k)^2 = r^2\)
  • We need to identify h, k, and r values

2. TRANSLATE the x-term to find h

  • \((x - 1)^2\) matches \((x - h)^2\)
  • Therefore: \(h = 1\)

3. TRANSLATE the y-term to find k

  • \((y + 7)^2\) needs to match \((y - k)^2\)
  • Rewrite: \((y + 7)^2 = (y - (-7))^2\)
  • Therefore: \(k = -7\)

4. INFER the center coordinates

  • Since \((h, k)\) represents the center in standard form
  • Center = \((1, -7)\)

Answer: C. (1, -7)


Why Students Usually Falter on This Problem

Most Common Error Path:

Weak TRANSLATE reasoning: Students incorrectly handle the signs when identifying k from \((y + 7)^2\).

They see \((y + 7)^2\) and think "\(k = +7\)" instead of recognizing that \((y + 7)^2 = (y - (-7))^2\), so \(k = -7\). This sign error is especially common because students rush through the pattern matching without carefully considering what the standard form actually requires.

This may lead them to select Choice D (1, 7).

The Bottom Line:

The key challenge is correctly handling the sign conversion in the y-term. Students must recognize that \((y + 7)^2\) means we're subtracting negative 7, not positive 7, from y in the standard form.

Answer Choices Explained
A
\((-1, -7)\)
B
\((-1, 7)\)
C
\((1, -7)\)
D
\((1, 7)\)
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