A certain park has an area of 11,863,808 square yards. What is the area, in square miles, of this park?...
GMAT Problem-Solving and Data Analysis : (PS_DA) Questions
A certain park has an area of \(11,863,808\) square yards. What is the area, in square miles, of this park?
(\(1\text{ mile} = 1,760\text{ yards}\))
\(1.96\)
\(3.83\)
\(3,444.39\)
\(6,740.8\)
1. TRANSLATE the problem information
- Given information:
- Park area: 11,863,808 square yards
- Linear conversion: \(\mathrm{1\text{ mile} = 1,760\text{ yards}}\)
- What we need: Area in square miles
2. INFER the area conversion relationship
- Key insight: Since we're converting area (square units), we need to square the linear conversion factor
- If \(\mathrm{1\text{ mile} = 1,760\text{ yards}}\), then \(\mathrm{1\text{ square mile} = (1,760\text{ yards})^2}\)
- This gives us: \(\mathrm{1\text{ square mile} = 1,760^2\text{ square yards}}\)
3. SIMPLIFY to find square yards per square mile
- Calculate: \(\mathrm{1,760^2 = 3,097,600\text{ square yards per square mile}}\) (use calculator)
4. SIMPLIFY the unit conversion
- Divide the given area by our conversion factor:
- \(\mathrm{11,863,808\text{ square yards} \div 3,097,600\text{ square yards per square mile}}\)
- \(\mathrm{= 3.83\text{ square miles}}\) (use calculator)
Answer: B. 3.83
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak INFER skill: Students forget that area conversion requires squaring the linear conversion factor
Students might think: "1 mile = 1,760 yards, so I just divide by 1,760"
This gives them: \(\mathrm{11,863,808 \div 1,760 = 6,740.8}\)
This may lead them to select Choice D (6,740.8)
Second Most Common Error:
Poor SIMPLIFY execution: Arithmetic errors in calculating \(\mathrm{1,760^2}\) or the final division
Students may incorrectly calculate \(\mathrm{1,760^2}\) or make division errors, leading to answers that don't match any choice exactly. This causes them to get stuck and guess.
The Bottom Line:
The key challenge is recognizing that area conversions require squaring the linear conversion factor. Many students apply linear conversion logic to area problems, missing this crucial step.
\(1.96\)
\(3.83\)
\(3,444.39\)
\(6,740.8\)