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Which of the following equations represents a circle in the xy-plane that intersects the y-axis at exactly one point?

GMAT Geometry & Trigonometry : (Geo_Trig) Questions

Source: Practice Test
Geometry & Trigonometry
Circles
HARD
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Notes
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Which of the following equations represents a circle in the \(\mathrm{xy}\)-plane that intersects the \(\mathrm{y}\)-axis at exactly one point?

A

\((\mathrm{x} - 8)^2 + (\mathrm{y} - 8)^2 = 16\)

B

\((\mathrm{x} - 8)^2 + (\mathrm{y} - 4)^2 = 16\)

C

\((\mathrm{x} - 4)^2 + (\mathrm{y} - 9)^2 = 16\)

D

\(\mathrm{x}^2 + (\mathrm{y} - 9)^2 = 16\)

Solution

1. TRANSLATE the problem requirement

  • Given: Four circle equations in standard form
  • Need: Circle that intersects y-axis at exactly one point
  • INFER what this means: "Intersects at exactly one point" = tangent to the y-axis

2. INFER the geometric condition for tangency

  • For a circle to be tangent to the y-axis, the distance from its center to the y-axis must equal its radius
  • Distance from point (h, k) to y-axis = |h|
  • Therefore: For tangency to y-axis, we need \(|h| = r\)

3. TRANSLATE each equation to find center and radius

For standard form \((x - h)^2 + (y - k)^2 = r^2\):

Choice A: \((x - 8)^2 + (y - 8)^2 = 16\)
• Center: (8, 8), radius = \(\sqrt{16} = 4\)

Choice B: \((x - 8)^2 + (y - 4)^2 = 16\)
• Center: (8, 4), radius = 4

Choice C: \((x - 4)^2 + (y - 9)^2 = 16\)
• Center: (4, 9), radius = 4

Choice D: \(x^2 + (y - 9)^2 = 16\)
• Center: (0, 9), radius = 4

4. APPLY CONSTRAINTS using the tangency condition

Check if \(|h| = r\) for each circle:

  • Choice A: \(|8| = 8\), but \(r = 4\)\(8 \neq 4\)
  • Choice B: \(|8| = 8\), but \(r = 4\)\(8 \neq 4\)
  • Choice C: \(|4| = 4\), and \(r = 4\)\(4 = 4\)
  • Choice D: \(|0| = 0\), but \(r = 4\)\(0 \neq 4\)

Answer: C




Why Students Usually Falter on This Problem

Most Common Error Path:

Weak INFER skill: Students don't connect "intersects y-axis at exactly one point" with the concept of tangency. Instead, they might try to substitute \(x = 0\) into each equation and count intersection points algebraically, which is much more complex and time-consuming. This approach often leads to calculation errors and confusion about what the results mean geometrically.

This leads to confusion and guessing among the choices.

Second Most Common Error:

Conceptual confusion about distance: Students might incorrectly think the distance from center (h, k) to the y-axis is k (the y-coordinate) instead of |h| (absolute value of x-coordinate). This fundamental misunderstanding about coordinate geometry makes it impossible to set up the correct tangency condition.

This may lead them to incorrectly analyze the equations and select Choice D since it has the center on the y-axis, thinking this creates tangency.

The Bottom Line:

This problem tests whether students can connect geometric concepts (tangency) with algebraic representations (circle equations). The key insight is recognizing that tangency creates a specific distance relationship, not just solving for intersection points algebraically.

Answer Choices Explained
A

\((\mathrm{x} - 8)^2 + (\mathrm{y} - 8)^2 = 16\)

B

\((\mathrm{x} - 8)^2 + (\mathrm{y} - 4)^2 = 16\)

C

\((\mathrm{x} - 4)^2 + (\mathrm{y} - 9)^2 = 16\)

D

\(\mathrm{x}^2 + (\mathrm{y} - 9)^2 = 16\)

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