Question:A circle in the xy-plane is defined by the equation \((\mathrm{x} + 10)^2 + (\mathrm{y} - 8)^2 = 100\). What...
GMAT Geometry & Trigonometry : (Geo_Trig) Questions
A circle in the xy-plane is defined by the equation \((\mathrm{x} + 10)^2 + (\mathrm{y} - 8)^2 = 100\). What are the coordinates of the center of the circle?
- \((-10, -8)\)
- \((-10, 8)\)
- \((10, -8)\)
- \((10, 8)\)
1. TRANSLATE the equation to standard form
- Given equation: \((\mathrm{x} + 10)^2 + (\mathrm{y} - 8)^2 = 100\)
- Standard form of circle: \((\mathrm{x} - \mathrm{h})^2 + (\mathrm{y} - \mathrm{k})^2 = \mathrm{r}^2\)
- The center is at point \((\mathrm{h}, \mathrm{k})\)
2. INFER the center coordinates by comparing formats
- For the x-term: \((\mathrm{x} + 10)^2\) needs to match \((\mathrm{x} - \mathrm{h})^2\)
- Since \((\mathrm{x} + 10) = (\mathrm{x} - (-10))\), we have \(\mathrm{h} = -10\)
- For the y-term: \((\mathrm{y} - 8)^2\) already matches \((\mathrm{y} - \mathrm{k})^2\)
- So \(\mathrm{k} = 8\)
3. TRANSLATE the mathematical result to coordinates
- Center coordinates: \((\mathrm{h}, \mathrm{k}) = (-10, 8)\)
Answer: B \((-10, 8)\)
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak TRANSLATE skill: Students incorrectly handle the signs when matching to standard form.
They see \((\mathrm{x} + 10)^2\) and think \(\mathrm{h} = +10\), not recognizing that \((\mathrm{x} + 10)^2 = (\mathrm{x} - (-10))^2\). This leads them to identify the center as \((10, 8)\) instead of \((-10, 8)\).
This may lead them to select Choice D \((10, 8)\).
Second Most Common Error:
Incomplete TRANSLATE reasoning: Students get confused about which coordinate corresponds to which variable.
They might correctly find \(\mathrm{h} = -10\) and \(\mathrm{k} = 8\), but then mix up the order and report the center as \((8, -10)\) or make other coordinate ordering errors. While this specific error doesn't match any given choice exactly, it causes confusion and may lead to guessing.
The Bottom Line:
The key challenge is carefully tracking the signs when converting between \((\mathrm{x} + \mathrm{a})^2\) and \((\mathrm{x} - \mathrm{h})^2\) formats. The equation gives you the center directly, but only if you handle the algebra notation correctly.