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On January 1, 2015, a city's minimum hourly wage was $9.25. It will increase by $0.50 on the first day...

GMAT Algebra : (Alg) Questions

Source: Official
Algebra
Linear functions
EASY
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On January 1, 2015, a city's minimum hourly wage was \(\$9.25\). It will increase by \(\$0.50\) on the first day of the year for the next 5 years. Which of the following functions best models the minimum hourly wage, in dollars, x years after January 1, 2015, where \(\mathrm{x = 1, 2, 3, 4, 5}\)?

A
\(\mathrm{f(x) = 9.25 - 0.50x}\)
B
\(\mathrm{f(x) = 9.25x - 0.50}\)
C
\(\mathrm{f(x) = 9.25 + 0.50x}\)
D
\(\mathrm{f(x) = 9.25x + 0.50}\)
Solution

1. TRANSLATE the problem information

  • Given information:
    • Starting wage on January 1, 2015: \(\$9.25\)
    • Annual increase: \(\$0.50\) each year for 5 years
    • Need function for wage x years after January 1, 2015

2. INFER the mathematical relationship

  • This describes a linear relationship where:
    • The wage starts at a fixed amount (\(\$9.25\))
    • The wage increases by a constant amount (\(\$0.50\)) each year
  • This matches the linear function form \(\mathrm{f(x) = mx + b}\) where:
    • \(\mathrm{b}\) = initial value = \(\$9.25\)
    • \(\mathrm{m}\) = rate of change = \(\$0.50\) per year

3. Build and verify the function

  • Construct: \(\mathrm{f(x) = 9.25 + 0.50x}\)
  • Test with a few values:
    • \(\mathrm{x = 1}\): \(\mathrm{f(1) = 9.25 + 0.50(1) = \$9.75}\)
    • \(\mathrm{x = 2}\): \(\mathrm{f(2) = 9.25 + 0.50(2) = \$10.25}\)

4. Check against answer choices

  • Choice A: \(\mathrm{f(x) = 9.25 - 0.50x}\) shows decreasing wage
  • Choice B: \(\mathrm{f(x) = 9.25x - 0.50}\) multiplies wage by years
  • Choice C: \(\mathrm{f(x) = 9.25 + 0.50x}\) matches our model ✓
  • Choice D: \(\mathrm{f(x) = 9.25x + 0.50}\) multiplies wage by years

Answer: C




Why Students Usually Falter on This Problem


Most Common Error Path:

Weak TRANSLATE reasoning: Students misinterpret "increase by \(\$0.50\)" and think the wage gets multiplied by something involving \(\$0.50\), or they confuse which number represents the starting amount versus the change amount.

For example, they might think since the wage "increases," they need to multiply \(\$9.25\) by something, leading them to incorrectly select Choice B (\(\mathrm{f(x) = 9.25x - 0.50}\)) or Choice D (\(\mathrm{f(x) = 9.25x + 0.50}\)).


Second Most Common Error:

Poor TRANSLATE execution: Students correctly identify that wages are increasing but accidentally use subtraction instead of addition, perhaps because they're thinking about the calculation backwards or making a sign error.

This may lead them to select Choice A (\(\mathrm{f(x) = 9.25 - 0.50x}\)), which would show wages decreasing over time.


The Bottom Line:

Success requires carefully translating the word problem to identify what stays constant (the \(\$9.25\) starting wage) versus what changes (the \(\$0.50\) annual increase), then correctly building the linear function using these components.

Answer Choices Explained
A
\(\mathrm{f(x) = 9.25 - 0.50x}\)
B
\(\mathrm{f(x) = 9.25x - 0.50}\)
C
\(\mathrm{f(x) = 9.25 + 0.50x}\)
D
\(\mathrm{f(x) = 9.25x + 0.50}\)
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