A city's total expense budget for one year was x million dollars. The city budgeted y million dollars for departmental...
GMAT Algebra : (Alg) Questions
A city's total expense budget for one year was \(\mathrm{x}\) million dollars. The city budgeted \(\mathrm{y}\) million dollars for departmental expenses and 201 million dollars for all other expenses. Which of the following represents the relationship between \(\mathrm{x}\) and \(\mathrm{y}\) in this context?
\(\mathrm{x + y = 201}\)
\(\mathrm{x - y = 201}\)
\(\mathrm{2x - y = 201}\)
\(\mathrm{y - x = 201}\)
1. TRANSLATE the problem information
- Given information:
- Total expense budget: \(\mathrm{x}\) million dollars
- Departmental expenses: \(\mathrm{y}\) million dollars
- All other expenses: \(\mathrm{201}\) million dollars
2. INFER the mathematical relationship
- The total budget must equal the sum of all its parts
- This means: Total = Departmental expenses + Other expenses
- So: \(\mathrm{x = y + 201}\)
3. SIMPLIFY to match the answer format
- Starting with: \(\mathrm{x = y + 201}\)
- Subtract \(\mathrm{y}\) from both sides: \(\mathrm{x - y = 201}\)
- This matches choice B
Answer: B. \(\mathrm{x - y = 201}\)
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak TRANSLATE skill: Students misinterpret which quantity represents the total and which represent the parts.
They might think that since \(\mathrm{x}\) is the "total budget" and \(\mathrm{y}\) is "departmental expenses," they need to add them together, leading to the equation \(\mathrm{x + y = 201}\). They don't recognize that \(\mathrm{y}\) is actually a component of \(\mathrm{x}\), not separate from it.
This may lead them to select Choice A (\(\mathrm{x + y = 201}\)).
Second Most Common Error:
Poor INFER reasoning: Students correctly set up \(\mathrm{x = y + 201}\) but then get confused about which variable should be isolated.
They might think they need \(\mathrm{y}\) by itself and rearrange to get \(\mathrm{y = x - 201}\), then mistakenly flip this to match an answer choice, potentially selecting \(\mathrm{y - x = 201}\).
This may lead them to select Choice D (\(\mathrm{y - x = 201}\)).
The Bottom Line:
Success on this problem requires clearly identifying the part-whole relationship: the total budget \(\mathrm{x}\) contains both the departmental expenses \(\mathrm{y}\) and the other expenses \(\mathrm{201}\), so \(\mathrm{x = y + 201}\). Many students struggle because they don't carefully track which quantities are parts of the total versus separate from it.
\(\mathrm{x + y = 201}\)
\(\mathrm{x - y = 201}\)
\(\mathrm{2x - y = 201}\)
\(\mathrm{y - x = 201}\)