A cup of coffee is cooling in a room that is at a constant temperature of 70 degrees Fahrenheit. The...
GMAT Advanced Math : (Adv_Math) Questions
A cup of coffee is cooling in a room that is at a constant temperature of 70 degrees Fahrenheit. The difference between the temperature of the coffee and the room temperature is modeled by \(30 \times (\frac{2}{3})^\mathrm{t}\), where \(\mathrm{t}\) is the time in minutes after the coffee was poured. If the temperature of the coffee is graphed as a function of time in the \(\mathrm{xy}\)-plane, what is the \(\mathrm{y}\)-intercept of the graph?
1. TRANSLATE the problem information
- Given information:
- Room temperature: constant \(70°\mathrm{F}\)
- Temperature difference model: \(30 \times (\frac{2}{3})^\mathrm{t}\)
- t = time in minutes after coffee was poured
- Need to find: y-intercept of coffee temperature graph
- What this tells us: The model gives us the difference between coffee temperature and room temperature, not the actual coffee temperature.
2. INFER what the y-intercept represents
- The y-intercept occurs when \(\mathrm{t} = 0\) (initial time when coffee was poured)
- To find the actual coffee temperature, we need: \(\mathrm{Coffee\ temp} = \mathrm{Room\ temp} + \mathrm{Temperature\ difference}\)
- Strategy: Evaluate the difference at \(\mathrm{t} = 0\), then add room temperature
3. SIMPLIFY the exponential expression at t = 0
- Temperature difference at \(\mathrm{t} = 0\): \(30 \times (\frac{2}{3})^0\)
- Since any non-zero number raised to the 0 power equals 1: \((\frac{2}{3})^0 = 1\)
- Therefore: \(30 \times 1 = 30°\mathrm{F}\) difference
4. INFER the initial coffee temperature
- Coffee temperature = Room temperature + Temperature difference
- Coffee temperature = \(70 + 30 = 100°\mathrm{F}\)
- Y-intercept = \((0, 100)\)
Answer: C. (0, 100)
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak SIMPLIFY skill: Students incorrectly evaluate \((\frac{2}{3})^0\)
Many students think \((\frac{2}{3})^0 = 0\) because they confuse the exponent rule with multiplication by zero. This gives them a temperature difference of \(30 \times 0 = 0°\mathrm{F}\), leading to a coffee temperature of \(70 + 0 = 70°\mathrm{F}\).
This may lead them to select Choice A: (0, 70).
Second Most Common Error:
Poor TRANSLATE reasoning: Students mistake what the model represents
Some students think the expression \(30 \times (\frac{2}{3})^\mathrm{t}\) directly gives the coffee temperature, not realizing it represents the temperature difference. At \(\mathrm{t} = 0\), they get \(30°\mathrm{F}\) and think this is the coffee temperature.
This causes them to get stuck since 30 isn't an answer choice, leading to confusion and guessing.
The Bottom Line:
This problem requires careful attention to what the mathematical model actually represents (temperature difference, not absolute temperature) and solid knowledge of exponential function properties.