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A community kitchen starts the month with 3{,600} paper napkins in stock. The kitchen uses 45 napkins each day and...

GMAT Algebra : (Alg) Questions

Source: Prism
Algebra
Linear equations in 1 variable
EASY
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Notes
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A community kitchen starts the month with \(\mathrm{3{,}600}\) paper napkins in stock. The kitchen uses \(\mathrm{45}\) napkins each day and does not restock during this period. After how many days will the number of napkins remaining be equal to the number of napkins that have been used?

A

30

B

36

C

40

D

80

Solution

1. TRANSLATE the problem information

  • Given information:
    • Starting napkins: 3,600
    • Daily usage rate: 45 napkins per day
    • No restocking occurs
    • Need to find: when remaining napkins = used napkins
  • What this tells us: We need expressions for both "remaining" and "used" napkins after \(\mathrm{d}\) days

2. INFER the mathematical setup

  • Since we want remaining = used, we'll set up an equation
  • Let \(\mathrm{d}\) = number of days
  • After \(\mathrm{d}\) days: Used napkins = \(\mathrm{45d}\)
  • After \(\mathrm{d}\) days: Remaining napkins = \(\mathrm{3{,}600 - 45d}\)

3. TRANSLATE the key condition into an equation

  • "Remaining equals used" means: \(\mathrm{3{,}600 - 45d = 45d}\)

4. SIMPLIFY to solve for d

  • Add \(\mathrm{45d}\) to both sides: \(\mathrm{3{,}600 = 90d}\)
  • Divide both sides by 90: \(\mathrm{d = 3{,}600 \div 90 = 40}\)

5. Verify with alternative approach

  • INFER: If remaining = used, each portion is exactly half the total
  • Half of 3,600 = 1,800 napkins
  • Time to use 1,800 napkins: \(\mathrm{1{,}800 \div 45 = 40}\) days ✓

Answer: C (40 days)




Why Students Usually Falter on This Problem


Most Common Error Path:

Weak TRANSLATE reasoning: Students often struggle to correctly set up the "remaining napkins" expression, writing it as just \(\mathrm{45d}\) instead of \(\mathrm{3{,}600 - 45d}\).

Their thinking: "After \(\mathrm{d}\) days, there are \(\mathrm{45d}\) napkins remaining"

This fundamental misunderstanding of what "remaining" means leads to the wrong equation: \(\mathrm{45d = 45d}\), which gives no useful information. This causes confusion and typically leads to guessing among the answer choices.


Second Most Common Error:

Poor SIMPLIFY execution: Students correctly set up \(\mathrm{3{,}600 - 45d = 45d}\) but make arithmetic errors when solving.

Common mistakes include:

  • Getting \(\mathrm{3{,}600 = 45d}\) (forgetting to add \(\mathrm{45d}\) to both sides)
  • Calculating \(\mathrm{3{,}600 \div 45 = 80}\) instead of \(\mathrm{3{,}600 \div 90 = 40}\)

This may lead them to select Choice D (80) due to the incorrect division.


The Bottom Line:

This problem tests whether students can correctly interpret "remaining quantity" as "starting amount minus used amount" and then set up a proper equation. The key insight is recognizing that when two quantities are equal, you can solve by setting their algebraic expressions equal to each other.

Answer Choices Explained
A

30

B

36

C

40

D

80

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