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A linear function f gives a company's profit, in dollars, for selling x items. The company's profit is $220 when...

GMAT Algebra : (Alg) Questions

Source: Practice Test
Algebra
Linear functions
MEDIUM
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A linear function \(\mathrm{f}\) gives a company's profit, in dollars, for selling \(\mathrm{x}\) items. The company's profit is \($220\) when it sells \(8\) items, and its profit is \($320\) when it sells \(10\) items. Which equation defines \(\mathrm{f}\)?

A

\(\mathrm{f(x) = 150x - 320}\)

B

\(\mathrm{f(x) = 32x}\)

C

\(\mathrm{f(x) = 50x - 10x}\)

D

\(\mathrm{f(x) = 50x - 180}\)

Solution

1. TRANSLATE the problem information

  • Given information:
    • \(\mathrm{f(x)}\) = company's profit for selling \(\mathrm{x}\) items
    • When 8 items sold: profit = $220
    • When 10 items sold: profit = $320
    • \(\mathrm{f(x)}\) is linear
  • What this tells us: We have two coordinate points: \(\mathrm{(8, 220)}\) and \(\mathrm{(10, 320)}\)

2. INFER the solution strategy

  • Since \(\mathrm{f(x)}\) is linear, it has the form \(\mathrm{f(x) = mx + b}\)
  • Strategy: Find slope \(\mathrm{m}\) first, then find y-intercept \(\mathrm{b}\)
  • We'll use the slope formula, then substitute one point to find \(\mathrm{b}\)

3. SIMPLIFY to find the slope

  • Use slope formula: \(\mathrm{m = \frac{y_2 - y_1}{x_2 - x_1}}\)
  • With points \(\mathrm{(8, 220)}\) and \(\mathrm{(10, 320)}\):
    \(\mathrm{m = \frac{320 - 220}{10 - 8}}\)
    \(\mathrm{m = \frac{100}{2}}\)
    \(\mathrm{m = 50}\)

4. SIMPLIFY to find the y-intercept

  • Substitute \(\mathrm{m = 50}\) and point \(\mathrm{(8, 220)}\) into \(\mathrm{f(x) = mx + b}\):
    \(\mathrm{220 = 50(8) + b}\)
    \(\mathrm{220 = 400 + b}\)
    \(\mathrm{b = 220 - 400 = -180}\)

5. Write the final function

  • \(\mathrm{f(x) = 50x - 180}\)

Answer: D. \(\mathrm{f(x) = 50x - 180}\)




Why Students Usually Falter on This Problem


Most Common Error Path:

Weak SIMPLIFY execution: Students correctly set up the slope calculation but make arithmetic errors, such as calculating the slope as 32 instead of 50 (perhaps confusing 100/2 with some other calculation), or they assume the function passes through the origin (\(\mathrm{b = 0}\)).

For example, if they think the slope is 32 and \(\mathrm{b = 0}\), they get \(\mathrm{f(x) = 32x}\). This actually works for one point: \(\mathrm{f(10) = 320}\), which might seem to confirm their answer, but \(\mathrm{f(8) = 256 \neq 220}\).

This may lead them to select Choice B (\(\mathrm{f(x) = 32x}\)).


Second Most Common Error:

Poor TRANSLATE reasoning: Students might misinterpret which coordinate represents which value, or they might try to use the answer choices to work backwards without systematic calculation.

Some students see Choice C (\(\mathrm{f(x) = 50x - 10x}\)) and think it looks promising because it has the correct slope coefficient of 50, not realizing it simplifies to \(\mathrm{f(x) = 40x}\), which doesn't work for either given point.

This may lead them to select Choice C (\(\mathrm{f(x) = 50x - 10x}\)).


The Bottom Line:

This problem tests whether students can systematically apply the linear function process rather than taking shortcuts or making calculation errors. The key is recognizing that you must find both \(\mathrm{m}\) and \(\mathrm{b}\) through careful calculation, not just guess from answer choices.

Answer Choices Explained
A

\(\mathrm{f(x) = 150x - 320}\)

B

\(\mathrm{f(x) = 32x}\)

C

\(\mathrm{f(x) = 50x - 10x}\)

D

\(\mathrm{f(x) = 50x - 180}\)

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