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Functions f and g are defined by \(\mathrm{f(x) = 2x + k}\) and \(\mathrm{g(x) = x^2 - 3x}\). In the...

GMAT Advanced Math : (Adv_Math) Questions

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Functions \(\mathrm{f}\) and \(\mathrm{g}\) are defined by \(\mathrm{f(x) = 2x + k}\) and \(\mathrm{g(x) = x^2 - 3x}\). In the function \(\mathrm{f}\), \(\mathrm{k}\) is a constant. If the composite function \(\mathrm{g(f(x))}\) is equal to \(\mathrm{4x^2 + 18x + 18}\), what is the value of \(\mathrm{k}\)?

  1. -3
  2. 3
  3. 6
  4. 18
A

-3

B

3

C

6

D

18

Solution

1. TRANSLATE the composite function notation

  • Given information:
    • \(\mathrm{f(x) = 2x + k}\) (where k is unknown)
    • \(\mathrm{g(x) = x^2 - 3x}\)
    • \(\mathrm{g(f(x)) = 4x^2 + 18x + 18}\)
  • What \(\mathrm{g(f(x))}\) means: Substitute the entire expression \(\mathrm{f(x)}\) wherever you see x in \(\mathrm{g(x)}\)

2. TRANSLATE g(f(x)) into substitution form

  • \(\mathrm{g(f(x)) = g(2x + k)}\)
  • Now substitute \(\mathrm{(2x + k)}\) for every x in \(\mathrm{g(x)}\):
  • \(\mathrm{g(2x + k) = (2x + k)^2 - 3(2x + k)}\)

3. SIMPLIFY by expanding the algebraic expression

  • Expand \(\mathrm{(2x + k)^2}\):
    \(\mathrm{(2x + k)^2 = (2x)(2x) + 2(2x)(k) + k^2}\)
    \(\mathrm{= 4x^2 + 4kx + k^2}\)
  • Expand \(\mathrm{-3(2x + k)}\):
    \(\mathrm{-3(2x + k) = -6x - 3k}\)
  • Combine everything:
    \(\mathrm{g(f(x)) = 4x^2 + 4kx + k^2 - 6x - 3k}\)
    \(\mathrm{g(f(x)) = 4x^2 + (4k - 6)x + (k^2 - 3k)}\)

4. INFER the solution strategy from polynomial equality

  • We know: \(\mathrm{g(f(x)) = 4x^2 + 18x + 18}\)
  • We found: \(\mathrm{g(f(x)) = 4x^2 + (4k - 6)x + (k^2 - 3k)}\)
  • For these polynomials to be equal, their coefficients must match term by term

5. INFER the equations by comparing coefficients

  • \(\mathrm{x^2}\) coefficients: \(\mathrm{4 = 4}\) ✓ (this checks out)
  • x coefficients: \(\mathrm{4k - 6 = 18}\)
  • constant terms: \(\mathrm{k^2 - 3k = 18}\)

6. SIMPLIFY to solve for k

  • From the x coefficient equation:
    \(\mathrm{4k - 6 = 18}\)
    \(\mathrm{4k = 24}\)
    \(\mathrm{k = 6}\)

7. APPLY CONSTRAINTS by verifying the solution

  • Check using the constant term equation:
    \(\mathrm{k^2 - 3k = 6^2 - 3(6)}\)
    \(\mathrm{= 36 - 18}\)
    \(\mathrm{= 18}\)
  • Since \(\mathrm{18 = 18}\), our solution is correct

Answer: C




Why Students Usually Falter on This Problem


Most Common Error Path:

Weak TRANSLATE reasoning: Not understanding that \(\mathrm{g(f(x))}\) requires substituting the entire expression \(\mathrm{f(x) = 2x + k}\) into \(\mathrm{g(x)}\)

Students might try to work with \(\mathrm{g(f(x))}\) as separate functions or attempt to "multiply" g and f together. Some might substitute \(\mathrm{x = 2x + k}\) incorrectly, leading to confused algebraic manipulations.

This leads to confusion and guessing.


Second Most Common Error:

Poor SIMPLIFY execution: Making algebraic errors when expanding \(\mathrm{(2x + k)^2}\)

Students commonly expand this as \(\mathrm{4x^2 + k^2}\) (forgetting the middle term \(\mathrm{4kx}\)) or make sign errors when distributing \(\mathrm{-3(2x + k)}\). These errors create incorrect coefficient equations.

This may lead them to select Choice A (-3) or Choice B (3) depending on the specific algebraic mistake.


The Bottom Line:

This problem tests whether students can translate composite function notation into concrete substitution and then execute multi-step algebraic manipulation accurately. The conceptual hurdle is understanding what \(\mathrm{g(f(x))}\) actually means, while the execution challenge lies in errorless polynomial expansion.

Answer Choices Explained
A

-3

B

3

C

6

D

18

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Functions f and g are defined by \(\mathrm{f(x) = 2x + k}\) and \(\mathrm{g(x) = x^2 - 3x}\). In the function f, k is a constant. If the composite function \(\mathrm{g(f(x))}\) is equal to 4x^2 + 18x + 18, what is the value of k?-33618 : Advanced Math (Adv_Math)