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Connor has c dollars and Maria has m dollars. Connor has 4 times as many dollars as Maria, and together...

GMAT Algebra : (Alg) Questions

Source: Practice Test
Algebra
Systems of 2 linear equations in 2 variables
EASY
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Notes
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Connor has \(\mathrm{c}\) dollars and Maria has \(\mathrm{m}\) dollars. Connor has 4 times as many dollars as Maria, and together they have a total of \(\$25.00\). Which system of equations represents this situation?

A

\(\mathrm{c = 4m}\)
\(\mathrm{c + m = 25}\)

B

\(\mathrm{m = 4c}\)
\(\mathrm{c + m = 25}\)

C

\(\mathrm{c = 25m}\)
\(\mathrm{c + m = 4}\)

D

\(\mathrm{m = 25c}\)
\(\mathrm{c + m = 4}\)

Solution

1. TRANSLATE the problem information

  • Given information:
    • Connor has c dollars, Maria has m dollars
    • "Connor has 4 times as many dollars as Maria"
    • "together they have a total of $25.00"

2. TRANSLATE each relationship into an equation

  • "Connor has 4 times as many dollars as Maria":
    This means Connor's amount = 4 × Maria's amount
    So: \(\mathrm{c = 4m}\)
  • "together they have a total of $25.00":
    This means Connor's amount + Maria's amount = 25
    So: \(\mathrm{c + m = 25}\)

3. INFER that we need both equations together

  • Since both conditions must be true at the same time, we need a system of equations:
    \(\mathrm{c = 4m}\)
    \(\mathrm{c + m = 25}\)

4. Match with answer choices

Looking at the options, Choice A gives us exactly \(\mathrm{c = 4m}\) and \(\mathrm{c + m = 25}\).

Answer: A




Why Students Usually Falter on This Problem

Most Common Error Path:

Weak TRANSLATE skill: Students misinterpret "Connor has 4 times as many dollars as Maria" and write \(\mathrm{m = 4c}\) instead of \(\mathrm{c = 4m}\).

The phrase "Connor has 4 times as many" means Connor's amount equals 4 times Maria's amount, but students sometimes think it means Maria has 4 times Connor's amount. They get the relationship backwards.

This may lead them to select Choice B (\(\mathrm{m = 4c}\), \(\mathrm{c + m = 25}\)).


Second Most Common Error:

Poor TRANSLATE reasoning: Students mix up which numbers go where, potentially writing equations like \(\mathrm{c = 25m}\) or interpreting the total as $4 instead of $25.

This confusion about which numbers represent the multiplier versus the total can cause them to get stuck and guess, or select Choice C or Choice D.


The Bottom Line:

The key challenge is carefully translating "X has [number] times as many as Y" into the correct equation \(\mathrm{X = [number] \times Y}\), not the reverse. Students must slow down and think about which variable should equal the multiple of the other.

Answer Choices Explained
A

\(\mathrm{c = 4m}\)
\(\mathrm{c + m = 25}\)

B

\(\mathrm{m = 4c}\)
\(\mathrm{c + m = 25}\)

C

\(\mathrm{c = 25m}\)
\(\mathrm{c + m = 4}\)

D

\(\mathrm{m = 25c}\)
\(\mathrm{c + m = 4}\)

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