A content creator has 2{,}000 subscribers at the start of month 0 (when t = 0). Each month, the number...
GMAT Problem-Solving and Data Analysis : (PS_DA) Questions
A content creator has \(2{,}000\) subscribers at the start of month 0 (when \(\mathrm{t = 0}\)). Each month, the number of subscribers increases by \(0.49\%\) of the number of subscribers from the previous month. Let \(\mathrm{t}\) represent the number of months since the initial time point. Which of the following functions \(\mathrm{N(t)}\) best models the number of subscribers after \(\mathrm{t}\) months?
\(\mathrm{N(t) = 2000 + 0.0049t}\)
\(\mathrm{N(t) = 2000(1 - 0.0049)^t}\)
\(\mathrm{N(t) = 2000(1 + 0.0049)^t}\)
\(\mathrm{N(t) = 2000(1 + 0.0049t)}\)
1. TRANSLATE the problem information
- Given information:
- Initial subscribers: 2,000 at \(\mathrm{t = 0}\)
- Growth rate: \(\mathrm{0.49\%}\) per month
- Need: Function \(\mathrm{N(t)}\) for subscribers after t months
- What this tells us: Since subscribers increase by a fixed percentage each month, this is exponential growth, not linear growth.
2. INFER the correct mathematical model
- Key insight: When something grows by a fixed percentage each time period, we multiply by the same factor repeatedly
- A \(\mathrm{0.49\%}\) increase means we multiply by \(\mathrm{(1 + 0.0049) = 1.0049}\) each month
- This leads to the exponential growth formula: \(\mathrm{N(t) = N_0(1 + r)^t}\)
3. TRANSLATE the growth rate properly
- Convert \(\mathrm{0.49\%}\) to decimal: \(\mathrm{0.49\% = 0.0049}\)
- Growth factor becomes: \(\mathrm{(1 + 0.0049) = 1.0049}\)
4. APPLY the exponential growth formula
- \(\mathrm{N(t) = N_0(1 + r)^t}\)
- \(\mathrm{N(t) = 2000(1 + 0.0049)^t}\)
- \(\mathrm{N(t) = 2000(1.0049)^t}\)
5. INFER which answer choice matches
- Looking at the choices, only (C) has the form \(\mathrm{2000(1 + 0.0049)^t}\)
- All other choices represent either linear models or exponential decay
Answer: C
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak TRANSLATE skill: Students misinterpret "increases by \(\mathrm{0.49\%}\)" as meaning "add 0.49" or "add 0.0049" instead of "multiply by 1.0049."
They think: "If it increases by \(\mathrm{0.49\%}\), then each month we add 0.0049 to the previous amount." This additive thinking leads them to look for linear models.
This may lead them to select Choice (A) (\(\mathrm{N(t) = 2000 + 0.0049t}\)) or Choice (E) (\(\mathrm{N(t) = 2000 - 0.0049t}\)) depending on whether they remember the direction of change correctly.
Second Most Common Error:
Poor INFER reasoning: Students recognize it's exponential but confuse growth with decay, thinking that any change means the base factor should be less than 1.
They might think: "It's changing exponentially, so it must be like (1 - something)." This conceptual confusion about the relationship between growth/decay and factors greater/less than 1 leads to the wrong exponential form.
This may lead them to select Choice (B) (\(\mathrm{N(t) = 2000(1 - 0.0049)^t}\)).
The Bottom Line:
The key challenge is recognizing that percentage-based growth creates multiplicative relationships, not additive ones, and that growth corresponds to factors greater than 1.
\(\mathrm{N(t) = 2000 + 0.0049t}\)
\(\mathrm{N(t) = 2000(1 - 0.0049)^t}\)
\(\mathrm{N(t) = 2000(1 + 0.0049)^t}\)
\(\mathrm{N(t) = 2000(1 + 0.0049t)}\)