A cup of coffee is cooling in a room that is at a constant temperature of 70 degrees Fahrenheit. The...
GMAT Advanced Math : (Adv_Math) Questions
A cup of coffee is cooling in a room that is at a constant temperature of \(70\) degrees Fahrenheit. The difference between the temperature of the coffee and the room temperature is modeled by \(30 \times (\frac{2}{3})^\mathrm{t}\), where \(\mathrm{t}\) is the time in minutes after the coffee was poured. If the temperature of the coffee is graphed as a function of time in the \(\mathrm{xy}\)-plane, what is the \(\mathrm{y}\)-intercept of the graph?
\((0, 70)\)
\((0, 90)\)
\((0, 100)\)
\((0, 115)\)
1. TRANSLATE the problem information
- Given information:
- Room temperature: constant 70°F
- Temperature difference model: \(30 \times (\frac{2}{3})^\mathrm{t}\)
- \(\mathrm{t}\) = time in minutes after coffee was poured
- Need to find: y-intercept of coffee temperature graph
- What this tells us: The model gives us the difference between coffee temperature and room temperature, not the actual coffee temperature.
2. INFER what the y-intercept represents
- The y-intercept occurs when \(\mathrm{t} = 0\) (initial time when coffee was poured)
- To find the actual coffee temperature, we need: Coffee temp = Room temp + Temperature difference
- Strategy: Evaluate the difference at \(\mathrm{t} = 0\), then add room temperature
3. SIMPLIFY the exponential expression at \(\mathrm{t} = 0\)
- Temperature difference at \(\mathrm{t} = 0\): \(30 \times (\frac{2}{3})^0\)
- Since any non-zero number raised to the 0 power equals 1: \((\frac{2}{3})^0 = 1\)
- Therefore: \(30 \times 1 = 30\)°F difference
4. INFER the initial coffee temperature
- Coffee temperature = Room temperature + Temperature difference
- Coffee temperature = \(70 + 30 = 100\)°F
- Y-intercept = \((0, 100)\)
Answer: C. (0, 100)
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak SIMPLIFY skill: Students incorrectly evaluate \((\frac{2}{3})^0\)
Many students think \((\frac{2}{3})^0 = 0\) because they confuse the exponent rule with multiplication by zero. This gives them a temperature difference of \(30 \times 0 = 0\)°F, leading to a coffee temperature of \(70 + 0 = 70\)°F.
This may lead them to select Choice A: \((0, 70)\).
Second Most Common Error:
Poor TRANSLATE reasoning: Students mistake what the model represents
Some students think the expression \(30 \times (\frac{2}{3})^\mathrm{t}\) directly gives the coffee temperature, not realizing it represents the temperature difference. At \(\mathrm{t} = 0\), they get 30°F and think this is the coffee temperature.
This causes them to get stuck since 30 isn't an answer choice, leading to confusion and guessing.
The Bottom Line:
This problem requires careful attention to what the mathematical model actually represents (temperature difference, not absolute temperature) and solid knowledge of exponential function properties.
\((0, 70)\)
\((0, 90)\)
\((0, 100)\)
\((0, 115)\)