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A cup of coffee is cooling in a room that is at a constant temperature of 70 degrees Fahrenheit. The...

GMAT Advanced Math : (Adv_Math) Questions

Source: Prism
Advanced Math
Nonlinear functions
MEDIUM
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A cup of coffee is cooling in a room that is at a constant temperature of \(70\) degrees Fahrenheit. The difference between the temperature of the coffee and the room temperature is modeled by \(30 \times (\frac{2}{3})^\mathrm{t}\), where \(\mathrm{t}\) is the time in minutes after the coffee was poured. If the temperature of the coffee is graphed as a function of time in the \(\mathrm{xy}\)-plane, what is the \(\mathrm{y}\)-intercept of the graph?

A

\((0, 70)\)

B

\((0, 90)\)

C

\((0, 100)\)

D

\((0, 115)\)

Solution

1. TRANSLATE the problem information

  • Given information:
    • Room temperature: constant 70°F
    • Temperature difference model: \(30 \times (\frac{2}{3})^\mathrm{t}\)
    • \(\mathrm{t}\) = time in minutes after coffee was poured
    • Need to find: y-intercept of coffee temperature graph
  • What this tells us: The model gives us the difference between coffee temperature and room temperature, not the actual coffee temperature.

2. INFER what the y-intercept represents

  • The y-intercept occurs when \(\mathrm{t} = 0\) (initial time when coffee was poured)
  • To find the actual coffee temperature, we need: Coffee temp = Room temp + Temperature difference
  • Strategy: Evaluate the difference at \(\mathrm{t} = 0\), then add room temperature

3. SIMPLIFY the exponential expression at \(\mathrm{t} = 0\)

  • Temperature difference at \(\mathrm{t} = 0\): \(30 \times (\frac{2}{3})^0\)
  • Since any non-zero number raised to the 0 power equals 1: \((\frac{2}{3})^0 = 1\)
  • Therefore: \(30 \times 1 = 30\)°F difference

4. INFER the initial coffee temperature

  • Coffee temperature = Room temperature + Temperature difference
  • Coffee temperature = \(70 + 30 = 100\)°F
  • Y-intercept = \((0, 100)\)

Answer: C. (0, 100)




Why Students Usually Falter on This Problem

Most Common Error Path:

Weak SIMPLIFY skill: Students incorrectly evaluate \((\frac{2}{3})^0\)

Many students think \((\frac{2}{3})^0 = 0\) because they confuse the exponent rule with multiplication by zero. This gives them a temperature difference of \(30 \times 0 = 0\)°F, leading to a coffee temperature of \(70 + 0 = 70\)°F.

This may lead them to select Choice A: \((0, 70)\).

Second Most Common Error:

Poor TRANSLATE reasoning: Students mistake what the model represents

Some students think the expression \(30 \times (\frac{2}{3})^\mathrm{t}\) directly gives the coffee temperature, not realizing it represents the temperature difference. At \(\mathrm{t} = 0\), they get 30°F and think this is the coffee temperature.

This causes them to get stuck since 30 isn't an answer choice, leading to confusion and guessing.

The Bottom Line:

This problem requires careful attention to what the mathematical model actually represents (temperature difference, not absolute temperature) and solid knowledge of exponential function properties.

Answer Choices Explained
A

\((0, 70)\)

B

\((0, 90)\)

C

\((0, 100)\)

D

\((0, 115)\)

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