A manufacturer designs a shipping box in the shape of a cube. The length of each edge of the box...
GMAT Geometry & Trigonometry : (Geo_Trig) Questions
A manufacturer designs a shipping box in the shape of a cube. The length of each edge of the box is \(\mathrm{x}\) inches. Which expression gives the volume, in cubic inches, of the box?
\(\mathrm{6x}\)
\(\mathrm{12x}\)
\(\mathrm{6x^2}\)
\(\mathrm{x^3}\)
1. TRANSLATE the problem information
- Given information:
- A cube-shaped shipping box
- Each edge length is x inches
- Need to find volume expression in cubic inches
2. INFER the appropriate formula
- Since we need volume of a cube, we must use the cube volume formula
- Volume of cube = \(\mathrm{(edge\ length)}^3\)
- This makes sense because volume measures 3-dimensional space \(\mathrm{(length} \times \mathrm{width} \times \mathrm{height)}\)
3. Apply the formula
- Substitute the edge length x into the volume formula:
- Volume = \(\mathrm{x}^3\) cubic inches
Answer: D (\(\mathrm{x}^3\))
Why Students Usually Falter on This Problem
Most Common Error Path:
Conceptual confusion about cube measurements: Students mix up volume with surface area because both involve the number 6 and \(\mathrm{x}^2\).
Surface area of a cube = \(6\mathrm{x}^2\) (6 faces, each with area \(\mathrm{x}^2\)), so students see this familiar pattern and incorrectly select Choice C (\(6\mathrm{x}^2\)) thinking it represents volume.
Second Most Common Error:
Weak INFER skill: Students don't recognize they need the volume formula and instead think about total edge length.
A cube has 12 edges, each of length x, so total edge length = \(12\mathrm{x}\). This leads them to select Choice B (\(12\mathrm{x}\)) even though this measures linear distance, not 3-dimensional volume.
The Bottom Line:
The key challenge is distinguishing between different cube measurements - volume (\(\mathrm{x}^3\)), surface area (\(6\mathrm{x}^2\)), and total edge length (\(12\mathrm{x}\)). Students must recognize that volume specifically requires cubing the edge length because volume measures 3-dimensional space.
\(\mathrm{6x}\)
\(\mathrm{12x}\)
\(\mathrm{6x^2}\)
\(\mathrm{x^3}\)