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In the xy-plane, a parabola has vertex \((-5, 16)\) and intersects the x-axis at two distinct points. If the equation...

GMAT Advanced Math : (Adv_Math) Questions

Source: Prism
Advanced Math
Nonlinear functions
HARD
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In the xy-plane, a parabola has vertex \((-5, 16)\) and intersects the x-axis at two distinct points. If the equation of the parabola is written in the form \(y = ax^2 + bx + c\), where \(a\), \(b\), and \(c\) are constants, which of the following could be the value of \(a - b + c\)?

A

7

B

16

C

19

D

24

Solution

1. TRANSLATE the problem information

  • Given information:
    • Vertex: \((-5, 16)\)
    • Parabola intersects x-axis at two distinct points
    • Equation form: \(\mathrm{y = ax^2 + bx + c}\)
    • Need to find possible value of \(\mathrm{a - b + c}\)

2. INFER what the expression \(\mathrm{a - b + c}\) represents

  • The key insight: \(\mathrm{a - b + c}\) is actually the value of the function when \(\mathrm{x = -1}\)
  • Here's why: \(\mathrm{y(-1) = a(-1)^2 + b(-1) + c}\)
    \(\mathrm{= a(1) - b + c}\)
    \(\mathrm{= a - b + c}\)
  • This transforms our problem from abstract algebra to concrete function evaluation

3. TRANSLATE to vertex form and evaluate

  • Using vertex form: \(\mathrm{y = a(x - h)^2 + k}\) with vertex \((-5, 16)\)
  • This gives us: \(\mathrm{y = a(x + 5)^2 + 16}\)
  • Now evaluate at \(\mathrm{x = -1}\): \(\mathrm{y(-1) = a(-1 + 5)^2 + 16}\)
    \(\mathrm{= a(4)^2 + 16}\)
    \(\mathrm{= 16a + 16}\)

4. INFER the constraint on parameter a

  • The vertex \((-5, 16)\) is above the x-axis (positive y-coordinate)
  • The parabola crosses the x-axis at two distinct points
  • For this to happen, the parabola must open downward
  • Therefore: \(\mathrm{a \lt 0}\)

5. APPLY CONSTRAINTS to eliminate answer choices

  • Since \(\mathrm{a \lt 0}\), we have: \(\mathrm{16a + 16 \lt 0 + 16 = 16}\)
  • So \(\mathrm{a - b + c \lt 16}\)
  • Checking choices:
    • (A) \(\mathrm{7 \lt 16}\) ✓ Possible
    • (B) \(\mathrm{16 = 16}\) ✗ Not less than 16
    • (C) \(\mathrm{19 \gt 16}\) ✗ Too large
    • (D) \(\mathrm{24 \gt 16}\) ✗ Too large

Answer: A




Why Students Usually Falter on This Problem


Most Common Error Path:

Weak INFER skill: Not recognizing that \(\mathrm{a - b + c}\) represents \(\mathrm{y(-1)}\)

Students often see "\(\mathrm{a - b + c}\)" as just an abstract algebraic expression and try to work directly with the standard form \(\mathrm{y = ax^2 + bx + c}\). Without the key insight that this expression equals the function value at \(\mathrm{x = -1}\), they get stuck trying to manipulate the general form or attempt to find specific values of a, b, and c. This leads to confusion and guessing.


Second Most Common Error:

Conceptual confusion about parabola orientation: Thinking that a positive vertex y-coordinate means \(\mathrm{a \gt 0}\)

Students might reason: "The vertex has \(\mathrm{y = 16 \gt 0}\), so the parabola opens upward, meaning \(\mathrm{a \gt 0}\)." This leads them to conclude that \(\mathrm{16a + 16 \gt 16}\), making choices (C) or (D) seem reasonable. This may lead them to select Choice C (19) or Choice D (24).


The Bottom Line:

This problem tests whether students can connect abstract algebraic expressions to concrete function evaluations, and whether they truly understand how parabola orientation relates to x-axis intersections rather than just vertex position.

Answer Choices Explained
A

7

B

16

C

19

D

24

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