A right circular cylinder has a circular base whose circumference is 22pi centimeters. The height of the cylinder is 6...
GMAT Geometry & Trigonometry : (Geo_Trig) Questions
A right circular cylinder has a circular base whose circumference is \(22\pi\) centimeters. The height of the cylinder is \(6\) centimeters. What is the volume, in cubic centimeters, of the cylinder?
\(132\pi\)
\(264\pi\)
\(726\pi\)
\(2{,}904\pi\)
1. TRANSLATE the problem information
- Given information:
- Circumference of circular base: \(\mathrm{C = 22\pi}\) cm
- Height of cylinder: \(\mathrm{h = 6}\) cm
- Need to find: Volume in cubic centimeters
2. INFER the solution strategy
- To find volume of a cylinder, I need the volume formula \(\mathrm{V = \pi r^2h}\)
- I have height (6 cm) but need radius
- The circumference can give me the radius using \(\mathrm{C = 2\pi r}\)
3. SIMPLIFY to find the radius
- Start with circumference formula: \(\mathrm{C = 2\pi r}\)
- Substitute known value: \(\mathrm{22\pi = 2\pi r}\)
- Divide both sides by \(\mathrm{2\pi}\): \(\mathrm{r = \frac{22\pi}{2\pi} = 11}\) cm
4. SIMPLIFY to find the volume
- Apply volume formula: \(\mathrm{V = \pi r^2h}\)
- Substitute known values: \(\mathrm{V = \pi(11)^2(6)}\)
- Calculate: \(\mathrm{V = \pi(121)(6) = 726\pi}\) cubic centimeters
Answer: (C) 726π
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak INFER skill: Students don't recognize they need to find radius first before applying the volume formula. They might try to directly use the circumference value (\(\mathrm{22\pi}\)) in place of radius in the volume formula, calculating something like \(\mathrm{V = \pi(22\pi)^2(6)}\), leading to a massively incorrect result that doesn't match any answer choice. This leads to confusion and guessing.
Second Most Common Error:
Calculation error in SIMPLIFY: Students correctly identify the strategy but make arithmetic mistakes when computing \(\mathrm{r = \frac{22\pi}{2\pi}}\) or when calculating \(\mathrm{\pi(11)^2(6)}\). For example, they might incorrectly calculate \(\mathrm{(11)^2 = 111}\) instead of \(\mathrm{121}\), leading to \(\mathrm{V = \pi(111)(6) = 666\pi}\), which doesn't match any given choice. This may lead them to select Choice (A) (132π) as the "closest" answer.
The Bottom Line:
This problem tests whether students can work backwards from circumference to radius before applying a volume formula. The key insight is recognizing the two-step process: circumference → radius → volume.
\(132\pi\)
\(264\pi\)
\(726\pi\)
\(2{,}904\pi\)