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A right circular cylinder has a base circumference of 24pi centimeters and a height of 5 centimeters. What is the...

GMAT Geometry & Trigonometry : (Geo_Trig) Questions

Source: Prism
Geometry & Trigonometry
Area and volume formulas
MEDIUM
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Notes
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A right circular cylinder has a base circumference of \(24\pi\) centimeters and a height of \(5\) centimeters. What is the volume, in cubic centimeters, of the cylinder?

  1. \(60\pi\)
  2. \(720\pi\)
  3. \(1440\pi\)
  4. \(2880\pi\)
A
\(60\pi\)
B
\(720\pi\)
C
\(1440\pi\)
D
\(2880\pi\)
Solution

1. TRANSLATE the problem information

  • Given information:
    • Right circular cylinder
    • Base circumference = 24π cm
    • Height = 5 cm
    • Need to find volume in cubic cm

2. INFER the approach needed

  • To find volume, we need \(\mathrm{V = \pi r^2h}\)
  • We have height (5 cm) but need radius
  • We can get radius from the given circumference using \(\mathrm{C = 2\pi r}\)

3. SIMPLIFY to find the radius

  • Start with circumference formula: \(\mathrm{C = 2\pi r}\)
  • Substitute known values: \(\mathrm{24\pi = 2\pi r}\)
  • Divide both sides by 2π: \(\mathrm{r = \frac{24\pi}{2\pi} = 12}\) cm

4. SIMPLIFY to calculate the volume

  • Use volume formula: \(\mathrm{V = \pi r^2h}\)
  • Substitute values: \(\mathrm{V = \pi(12)^2(5)}\)
  • Calculate: \(\mathrm{V = \pi(144)(5) = 720\pi}\) cubic cm

Answer: B (720π)




Why Students Usually Falter on This Problem

Most Common Error Path:

Weak SIMPLIFY skill: Students correctly find \(\mathrm{r = 12}\) but forget to square the radius in the volume formula.

They calculate \(\mathrm{V = \pi(12)(5) = 60\pi}\) instead of \(\mathrm{V = \pi(12)^2(5) = 720\pi}\). The volume formula requires \(\mathrm{r^2}\), but they use just \(\mathrm{r}\), treating it like finding the area of a rectangle instead of the area of a circle times height.

This leads them to select Choice A (60π).

Second Most Common Error:

Poor INFER reasoning: Students recognize they need the volume formula but incorrectly think they can use the diameter directly since circumference relates to the full width.

Since \(\mathrm{C = 24\pi}\) and they know \(\mathrm{C = 2\pi r}\), they might think 'diameter = 24' and use that in \(\mathrm{V = \pi(diameter)^2h = \pi(24)^2(5) = 2880\pi}\). They're conceptually confused about whether the volume formula uses radius or diameter.

This leads them to select Choice D (2880π).

The Bottom Line:

This problem tests whether students can chain together multiple formulas (circumference → radius → volume) and execute each step accurately. The key insight is recognizing that you must find radius as an intermediate step before applying the volume formula.

Answer Choices Explained
A
\(60\pi\)
B
\(720\pi\)
C
\(1440\pi\)
D
\(2880\pi\)
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