A right circular cylinder has a circular base with circumference 8pi inches and a height of 12 inches. What is...
GMAT Geometry & Trigonometry : (Geo_Trig) Questions
A right circular cylinder has a circular base with circumference \(8\pi\) inches and a height of \(12\) inches. What is the volume, in cubic inches, of the cylinder?
- \(48\pi\)
- \(96\pi\)
- \(192\pi\)
- \(768\pi\)
\(48\pi\)
\(96\pi\)
\(192\pi\)
\(768\pi\)
1. TRANSLATE the problem information
- Given information:
- Right circular cylinder with circumference = \(\mathrm{8\pi}\) inches
- Height = 12 inches
- Need to find: volume in cubic inches
2. INFER the solution strategy
- To find volume of a cylinder, we need the radius and height
- We have the height (12 inches) but need to find the radius
- We can use the given circumference to find the radius first
3. SIMPLIFY to find the radius
- Use the circumference formula: \(\mathrm{C = 2\pi r}\)
- Substitute known values: \(\mathrm{8\pi = 2\pi r}\)
- Divide both sides by \(\mathrm{2\pi}\): \(\mathrm{r = \frac{8\pi}{2\pi} = 4}\) inches
4. SIMPLIFY to calculate the volume
- Use cylinder volume formula: \(\mathrm{V = \pi r^2h}\)
- Substitute our values: \(\mathrm{V = \pi(4)^2(12)}\)
- Calculate: \(\mathrm{V = \pi(16)(12) = 192\pi}\) cubic inches
Answer: C (\(\mathrm{192\pi}\))
Why Students Usually Falter on This Problem
Most Common Error Path:
Conceptual confusion about radius vs diameter: Students might incorrectly think the circumference represents the diameter, leading them to use \(\mathrm{r = 8}\) instead of \(\mathrm{r = 4}\).
This would give \(\mathrm{V = \pi(8)^2(12) = \pi(64)(12) = 768\pi}\), causing them to select Choice D (\(\mathrm{768\pi}\)).
Second Most Common Error:
Weak SIMPLIFY execution: Students correctly find \(\mathrm{r = 4}\) but forget to square the radius in the volume formula, calculating \(\mathrm{V = \pi(4)(12)}\) instead of \(\mathrm{V = \pi(4)^2(12)}\).
This gives \(\mathrm{V = 48\pi}\), leading them to select Choice A (\(\mathrm{48\pi}\)).
The Bottom Line:
This problem tests whether students can work backwards from circumference to radius, then forwards to volume. The key insight is recognizing that circumference gives you the radius through \(\mathrm{C = 2\pi r}\), not that circumference equals diameter.
\(48\pi\)
\(96\pi\)
\(192\pi\)
\(768\pi\)