prismlearning.academy Logo
NEUR
N

A right circular cylinder has a circular base with circumference 8pi inches and a height of 12 inches. What is...

GMAT Geometry & Trigonometry : (Geo_Trig) Questions

Source: Prism
Geometry & Trigonometry
Area and volume formulas
MEDIUM
...
...
Notes
Post a Query

A right circular cylinder has a circular base with circumference \(8\pi\) inches and a height of \(12\) inches. What is the volume, in cubic inches, of the cylinder?

  1. \(48\pi\)
  2. \(96\pi\)
  3. \(192\pi\)
  4. \(768\pi\)
A

\(48\pi\)

B

\(96\pi\)

C

\(192\pi\)

D

\(768\pi\)

Solution

1. TRANSLATE the problem information

  • Given information:
    • Right circular cylinder with circumference = \(\mathrm{8\pi}\) inches
    • Height = 12 inches
    • Need to find: volume in cubic inches

2. INFER the solution strategy

  • To find volume of a cylinder, we need the radius and height
  • We have the height (12 inches) but need to find the radius
  • We can use the given circumference to find the radius first

3. SIMPLIFY to find the radius

  • Use the circumference formula: \(\mathrm{C = 2\pi r}\)
  • Substitute known values: \(\mathrm{8\pi = 2\pi r}\)
  • Divide both sides by \(\mathrm{2\pi}\): \(\mathrm{r = \frac{8\pi}{2\pi} = 4}\) inches

4. SIMPLIFY to calculate the volume

  • Use cylinder volume formula: \(\mathrm{V = \pi r^2h}\)
  • Substitute our values: \(\mathrm{V = \pi(4)^2(12)}\)
  • Calculate: \(\mathrm{V = \pi(16)(12) = 192\pi}\) cubic inches

Answer: C (\(\mathrm{192\pi}\))


Why Students Usually Falter on This Problem

Most Common Error Path:

Conceptual confusion about radius vs diameter: Students might incorrectly think the circumference represents the diameter, leading them to use \(\mathrm{r = 8}\) instead of \(\mathrm{r = 4}\).

This would give \(\mathrm{V = \pi(8)^2(12) = \pi(64)(12) = 768\pi}\), causing them to select Choice D (\(\mathrm{768\pi}\)).

Second Most Common Error:

Weak SIMPLIFY execution: Students correctly find \(\mathrm{r = 4}\) but forget to square the radius in the volume formula, calculating \(\mathrm{V = \pi(4)(12)}\) instead of \(\mathrm{V = \pi(4)^2(12)}\).

This gives \(\mathrm{V = 48\pi}\), leading them to select Choice A (\(\mathrm{48\pi}\)).

The Bottom Line:

This problem tests whether students can work backwards from circumference to radius, then forwards to volume. The key insight is recognizing that circumference gives you the radius through \(\mathrm{C = 2\pi r}\), not that circumference equals diameter.

Answer Choices Explained
A

\(48\pi\)

B

\(96\pi\)

C

\(192\pi\)

D

\(768\pi\)

Rate this Solution
Tell us what you think about this solution
...
...
Forum Discussions
Start a new discussion
Post
Load More
Similar Questions
Finding similar questions...
Previous Attempts
Loading attempts...
Similar Questions
Finding similar questions...
Parallel Question Generator
Create AI-generated questions with similar patterns to master this question type.