A data center began processing a large file of 874{,500} megabytes (MB) at the start of a workday. After 14...
GMAT Algebra : (Alg) Questions
A data center began processing a large file of \(\mathrm{874{,}500}\) megabytes (MB) at the start of a workday. After \(\mathrm{14}\) minutes of continuous processing, \(\mathrm{660{,}300}\) MB of the file remained to be processed. On average, approximately how many megabytes did the data center process each second?
210
255
786
15,300
1. TRANSLATE the problem information
- Given information:
- Initial file size: 874,500 MB
- Processing time: 14 minutes (continuous)
- Remaining file size: 660,300 MB
- Need to find: average megabytes processed per second
2. INFER the solution approach
- To find processing rate, we need: Rate = Amount Processed ÷ Time
- We don't have "amount processed" directly - we need to calculate it first
- The time is in minutes, but we need rate per second - unit conversion required
- Strategy: Find processed amount → Convert time → Calculate rate
3. Calculate the amount of data processed
SIMPLIFY the subtraction:
\(\mathrm{Amount\ processed = Initial\ size - Remaining\ size}\)
\(\mathrm{Amount\ processed = 874,500\ MB - 660,300\ MB = 214,200\ MB}\)
4. TRANSLATE time units for the rate calculation
Since we need rate per second:
\(\mathrm{Time\ in\ seconds = 14\ minutes × 60\ seconds/minute = 840\ seconds}\)
5. SIMPLIFY to find the processing rate
\(\mathrm{Rate = Amount\ processed ÷ Time\ in\ seconds}\)
\(\mathrm{Rate = 214,200\ MB ÷ 840\ seconds}\) (use calculator)
\(\mathrm{Rate = 255\ MB\ per\ second}\)
Answer: B. 255
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak INFER skill: Students try to use the remaining amount (660,300 MB) instead of calculating the processed amount first.
They might divide \(\mathrm{660,300 ÷ 840 = 786}\), leading them to select Choice C (786). This happens because they misinterpret "remaining to be processed" as "already processed."
Second Most Common Error:
Poor TRANSLATE reasoning: Students forget to convert minutes to seconds and calculate rate per minute instead of per second.
They correctly find 214,200 MB processed in 14 minutes, then calculate \(\mathrm{214,200 ÷ 14 = 15,300}\) MB per minute. This leads them to select Choice D (15,300), not realizing the question asks for rate per second.
The Bottom Line:
This problem tests whether students can work backwards from "what's left" to find "what was processed," while also managing unit conversions. The multi-step nature means one wrong turn early leads to completely wrong final answers.
210
255
786
15,300